Question

yo can someone help me im failin thiss class

Answer 1

I can't read it- ;-;

Answer 2

Oh lol I just did this last unitttt

Answer 3

Did you do the 3 triangles thing in class where you have to make proportions for each triangle to find the sides?

Answer 4

yuh

Answer 5

So do you remember how to do it?

Answer 6

That theory won't work here, Devum. I think these are Spec. Triangles, correct me if I'm wrong.

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @CodexTheMemerLol
That theory won't work here, Devum. I think these are Spec. Triangles, correct me if I'm wrong.
\(\color{#0cbb34}{\text{End of Quote}}\)
Special triangles?

Answer 8

Mhm. 30-60-90, and 45-45-90 triangles. I could be wrong.

Answer 9

Would it not still work tho? You match up the 90 degrees on each of the triangles and compare proportions ;-;

Answer 10

It could work, but since there are radicals it would be much more efficient than just simplifying a decimal to a radical.

Answer 11

Radical to decimal conversion is torture as you have to pull yourself out of a hole that you could just jump in. Kinda like gearing up and down in physics.

Answer 12

\(\color{#0cbb34}{\text{Originally Posted by}}\) @CodexTheMemerLol
It could work, but since there are radicals it would be much more efficient than just simplifying a decimal to a radical.
\(\color{#0cbb34}{\text{End of Quote}}\)
Oh I don't think we did that in class yet ;-;, you mind showing me an example?

Answer 13

Sure. Say for example, there is a triangle where the angles are 45-45-90, the hypotenuse is 4 sqrt(2). This means that the legs would be 4. For a 30-60-90 triangle, the hypotenuse is the same. The long leg would be 8, and the small side would be 4.

Answer 14

Both scenarios are the same. Proportions are close to impossible with questions like these.

Answer 15

\(\color{#0cbb34}{\text{Originally Posted by}}\) @CodexTheMemerLol
Sure. Say for example, there is a triangle where the angles are 45-45-90, the hypotenuse is 4 sqrt(2). This means that the legs would be 4. For a 30-60-90 triangle, the hypotenuse is the same. The long leg would be 8, and the small side would be 4.
\(\color{#0cbb34}{\text{End of Quote}}\)
Ohhh yeah I remember. We did that

Answer 16

\(\color{#0cbb34}{\text{Originally Posted by}}\) @CodexTheMemerLol
Sure. Say for example, there is a triangle where the angles are 45-45-90, the hypotenuse is 4 sqrt(2). This means that the legs would be 4. For a 30-60-90 triangle, the hypotenuse is the same. The long leg would be 8, and the small side would be 4.
\(\color{#0cbb34}{\text{End of Quote}}\)
Like this?

Answer 17

nah these problems aren't special right triangle problems. The ones posted at the top as @Devum said earlier will require you to make proportions,

Answer 18

waitt what

Answer 19

so how i ve saw these posted triangles in more cases you need to use the altitude theorem

In a right triangle, the altitude drawn to the hypotenuse c divides the hypotenuse into two segments of lengths p and q. If we denote the length of the altitude by hc, we then have the relation


\[h_c = \sqrt{pq}\]

Answer 20

@Laylalyssa

Answer 21

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
@Laylalyssa
\(\color{#0cbb34}{\text{End of Quote}}\)
idk this...

Answer 22

you dont learn about altitude theorem ?

Answer 23

@darkknight