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tarahn:

help plz 2/3(5x + 7) + 3x

tarahn:

0_0

tarahn:

plz

rocfp:

First Combine multiplied term into a single fraction, second Distribute and if I am correct the answer should be 10x +14/3 +3x

Lexih:

10x+14/3+3x

rocfp:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @rocfp First Combine multiplied term into a single fraction, second Distribute and if I am correct the answer should be 10x +14/3 +3x \(\color{#0cbb34}{\text{End of Quote}}\) Although, I should of let you tried it BEFORE I answered but, I hope you understand what to do for the next problem

Astrid1:

Okay so what you are going to want to do is Combine multiplied terms into a single fraction. \[\frac{ 2 }{ 3 } (5x+7) +3x\] \[\frac{ 2(5x+7) }{ 3 } + 3x\] Then you are going to want to distribute. \[\frac{ 2 (5x+7) }{ 3} + 3x\] \[\frac{ 10x+14 }{ 3 } +3x\]

Astrid1:

Now try and solve to get your Answer.

tarahn:

ok..

Astrid1:

Once you're done with that you should get the answer that @rocfp gave you.

supie:

I believe the first step is to distribute \(\frac12\) to everything inside the parenthesis (5x and 7) \(\LARGE\frac{2}{3}(5x+7)+3x \longrightarrow (\frac{2}{3})(5x)+(\frac{2}{3})(7)+3x\) Then just simplify from the equation \((\frac{2}{3})(5x)+(\frac{2}{3})(7)+3x\) Multiply \(\frac{2}{3}\) and \(5x\) and multiply \(\frac{2}{3}\) and \(7\) We should get \(\frac{10}{3}x+\frac{14}{3}+3x\) Because \(\frac{2}{3}(5x)\rightarrow\ (\frac235)(x)\longrightarrow \frac{10}{3}x\) And \(\frac23 \times 7\longrightarrow \frac{2}{3} \times \frac{7}{1} \sf(because~7=\frac{7}{1})\) Multiply straight across from \(\frac23 \times \frac71\) Then you get \(\frac{14}{3}\) Therefore, you get \(\frac{10}{3}x+\frac{14}{3}+3x\) overall. Next we combine like terms which are \(\frac{10}{3}x\) and \(3x\) So we flip the equation so that it is now \(\frac{10}{3}x+3x+\frac{14}{3}\) Then add \(\frac{10}{3}x\) and \(3x\) which gives us \(\frac{?}{?}x\) (\(\frac{10}{3}x+3x=\frac{?}{?}\)) So once you get what 10/3x+3x equals then you would basically have your answer just keep 14/3 in the equation the original equation was \(\color{red}{\frac{10}{3}x+3x}+\frac{14}{3}\) So then \(\color{Red}{\frac{?}{?}x}+\frac{14}{3}\)

tarahn:

thx

supie:

np

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