Given the functions a(x) = 3x − 12 and b(x) = x − 9, solve a[b(x)].

a[b(x)] = 3x2 − 21
a[b(x)] = 3x2 − 39
a[b(x)] = 3x − 21
a[b(x)] = 3x − 39

Question

Given the functions a(x) = 3x − 12 and b(x) = x − 9, solve a[b(x)].

a[b(x)] = 3x2 − 21
 a[b(x)] = 3x2 − 39
 a[b(x)] = 3x − 21
 a[b(x)] = 3x − 39

xxDeppressionxx · Answer

a(x) = 3x - 12 b(x) = x - 9 a(b(x)) = a(x - 9) = 3(x - 9) - 12 = 3x - 27 - 12 = 3x - 39 a(b(x)) = 3x - 39 option (d) is correct: (a[b(x)] = 3x − 39)

LeBeanMan · Answer

Thx :)

xxDeppressionxx · Answer

Np