...
@jimthompson5910
Hint: A point like (1,5) reflects over this line to arrive at (5,1) Note how x and y swap places
so it would be the y = -x ?
close but no
the y-axis
Here's an example I found online. The diagram shows the upward opening parabola reflected over the line to get the sideways parabola. In other words, the dashed line is the line of reflection.
it won't let me graph the problem
Any idea what the equation of that dashed line might be?
wassup my g's
I thought it was going to be on the y line
i said "WASSUP MY G'S
TwT
\(\color{#0cbb34}{\text{Originally Posted by}}\) @sackbobdj202 i said "WASSUP MY G'S \(\color{#0cbb34}{\text{End of Quote}}\) STOP
nahh
T_T
\(\color{#0cbb34}{\text{Originally Posted by}}\) @hhanan I thought it was going to be on the y line \(\color{#0cbb34}{\text{End of Quote}}\)
Two points on the dashed line are (1,1) and (2,2) What do you notice about the coordinates?
there on the x part?
Do you agree that the coordinates for (1,1) are the same?
no?
(1,1) means that x = 1 and y = 1 Any point is of the form (x,y)
ya then
Any point on that dashed line has their x and y coordinates equal to one another. This means the equation of that dashed line is y = x
Join our real-time social learning platform and learn together with your friends!