I am still not understanding this... SS below
what grade are you in?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @DumbFounded what grade are you in? \(\color{#0cbb34}{\text{End of Quote}}\) 8th
damn i dont want to learn about that stuff it seems hard
@jhonyy9 Can you help? It's the same as last time, I am not understanding it at all.
this was solved past 2-3 days ago
Ik, I am not understanding it tho.
The formula for switching between diameter and radius is: \(Diameter = 2\times radius\) This is why the first column first box will have 6 as it's answer because 2x3=6
That means that in the second row, second box if we start with a Diameter of 12, then the radius will be half of that
So it would be 66 for the second row?
I'll assume that's a typo. you mean 6?
Yeah I mean 6.
then yes :)
Okay..
how about fourth row? converting from diameter of 8 what would be the radius?
4?
perfect!
Okay, Thanks!
how about sixth row? starting with radius of 10 what is the diameter?
20?
awesome! and seventh row: starting with diameter of 20, what is the radius?
10?
fantastic ok, so I think you are good at switching between the diameter and radius columns let's take a look at another column...
Okay..
The area of the base of this shape = \(\large \pi (radius)^2\)
So in the first row, third box, if the radius is 3 then \(\pi\times(3)\times (3)=?\)
you can keep pi in your answer
Okay...
Answer would be: 28.2743338823?
what I meant when I said to keep pi in your answer is \(\pi\times3\times3=9\pi\)
Oh, Okay. I used a calculator ngl.
ok let's try the next row for the same idea we said that the radius would be 6 area of base = \((radius)\times(radius)\times\pi\) what is 6 x 6 = ?
=36π
you got it!
Yay, Okay what's next?
how about the fourth row? radius = 4 area of base = \((radius)\times(radius)\times\pi\) what is 4 x 4 = ?
16π?
amazing! you can use the same ideas to fill the third box in the sixth and seventh rows too
Okay, Thanks so much!
wait... we're not really done yet...
but ok I guess
Yah, I still need help on the 5th one down.
The Diameter and radius are empty, And I don't know how to solve for those.
the hardest part in this problem is switching between the volume and other information the volume = (area of the base) x (height) or height = (volume) \(\div\) (area of the base) or area of the base = (volume) \(\div\) (height) ^ those three things I just wrote are the SAME formula - just in a different order so that you can pick which one you want to use depending on what information you are solving for. for example second row: we know the (area of the base) = 36 pi we also know that (volume) = 108 pi this means we use the second formula I wrote above because we are looking for the (height) height = (volume) \(\div\) (area of the base) = \((108\pi)\div(36\pi)=~?\)
While solving for the height in the second row I got 30.84472787, Would I have to round it? If so, What would I round it to?
whoa there what is 108 \(\div\) 36 = ?
I used pie in my division, Which may have turned my answer around.
So it would be 3
correct
let's look at the third row next area of the base = (volume) ÷ (height) we know that (volume) = 99pi and heigh = 11 what is 99 \(\div\) 11=?
9?
yup so the area of the base for the third row is 9 pi
then if you have (area of the base) = 9 pi what number times itself = 9? (that would be your radius)
3
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