Question

Jason has two bags with 6 tiles each. The tiles in each bag are shown below:

Make 6 squares. The squares are numbered sequentially from 1 to 6.

Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing an even tile from the first bag and an even tile from the second bag?

6 over 12
9 over 12
6 over 36
9 over 36

Answer 1

Because this is an "AND" question, we will be multiplying two probabilities

We want:
(prob of even tile from first bag) x (prob of even tile from second bag) = (combined prob)

Answer 2

what's the probability of getting an even tile from the first bag?

Answer 3

the probability is 1/6?

Answer 4

hmmm


out of 1, 2, 3, 4, 5, 6
what is the chance that I get an even number?

Answer 5

3%?

Answer 6

how'd you get 3%?

Answer 7

2, 4, and 6 are even
so the chance of getting an even number out of 1, 2, 3, 4, 5, 6
would be. 3 out of 6

Answer 8

because I count like 1 is odd 2 is even. so what I think 2 4 and 6 are even

Answer 9

ok but then we will have the fraction \(\large \frac{3}{6}\) because there are 6 numbers there total, so it won't be 3 percent, it would be 3 out of 6

Answer 10

oh ok

Answer 11

it would be the same probability for the second bag right?

Answer 12

yes

Answer 13

Then (prob of even tile from first bag) x (prob of even tile from second bag) = (combined prob)

which means:
\(\large \frac{3}{6}\times\frac{3}{6} =\) ?

Answer 14

9/36?

Answer 15

yup!

Answer 16

thank you for your help