Ag+ and SO42− What's the name of the ionic compound?
@MrMudd183
is it Silver (II) sulfate?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @iuytyuioiuytyuiop is it Silver (II) sulfate? \(\color{#0cbb34}{\text{End of Quote}}\) I think so
sulfate
That's correct!
thank you guys
\(\color{#0cbb34}{\text{Originally Posted by}}\) @iuytyuioiuytyuiop thank you guys \(\color{#0cbb34}{\text{End of Quote}}\) Np
Actually, I didn't see that you used two II Our silver atom has a 1+ charge
so its not the correct option?
Alternatively, you can just call it silver sulfate
the options are silver sulfate and another option is silver (ii) sulfate
Silver (ii) would have a +2 charge and so with sulfate \( (\text{SO}_4)^{-2}\) you would end up with \(\text{AgSO}_4\) to balance the charge
However, with \(\text{Ag}^{+}\) and \((\text{SO}_4)^{-2}\) to make a neutral polyatomic ion, we would need two silver (i) to balance the -2 from sulfate. That would get us \(\text{Ag}_2 \text{SO}_4\)
a Silver sulfate b Silver (II) sulfite c Silver (II) sulfate d Silver (I) sulfite
but its Ag2SO4
Exactly, which would make it silver sulfate
so its A
Yes
I thought the formula is Ag+SO42-
You have to balance the polyatomic ions so that the compound can be neutral. \(\text{Ag}^{+}\) has a +1 charge \((\text{SO}_4)^{-2}\) has a -2 charge That means we need \( 2~(\text{Ag}^{+})\) for \(1~(\text{SO}_4)^{-2}\) This will make it \( 2\text{Ag}^{+2}\) and \((\text{SO}_4)^{-2}\) The +2 and -2 can cancel each other out and we have ourselves the neutral silver sulfate compound. Also we have to move that 2 from the coefficient to a subscript so we get \(\text{Ag}_2 \text{SO}_4\)
i see
okay
It makes sense thank you
My pleasure!
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