Ask your own question, for FREE!
Biology 17 Online
ChrisTheFlash:

i need help with simplified slope-intercept form.

ChrisTheFlash:

this is the first question

UrGirlLily:

is this for a test or quiz?

UrGirlLily:

okie

ChrisTheFlash:

its from deltamath

UrGirlLily:

what grade r u in?

jkmiec26:

1 attachment
ChrisTheFlash:

10th

jkmiec26:

How many times did I go up and to the side?

jkmiec26:

and I'm in 10th to

ChrisTheFlash:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jkmiec26 How many times did I go up and to the side? \(\color{#0cbb34}{\text{End of Quote}}\) what is the awnser

jkmiec26:

can you open the image that I put?

ChrisTheFlash:

yes and i did

UrGirlLily:

I just think ur overthinking this.... Just gather the plotting info

UrGirlLily:

and im not being rude

UrGirlLily:

Put them in parenthesis

ChrisTheFlash:

im in a special math class for dyslexic people that is why i need the answer

ChrisTheFlash:

well can u give me the answer though?

AZ:

Slope-intercept form is y = mx + b where m is the slope and b is the y-intercept

AZ:

Do you know how to find the slope?

jkmiec26:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ Do you know how to find the slope? \(\color{#0cbb34}{\text{End of Quote}}\) btw he offline

AZ:

I noticed. Whenever he comes back- Slope is the rate of change. It can be found by rise/run which is how someone earlier described it. Here's an image that might help you visualize it better

1 attachment
AZ:

Another way to calculate the slope is by using a formula. First you have to pick any two points on the line. Let's call these points \( (x_1, ~y_1)\) and \( (x_2, ~y_2)\) The formula would be \( \text{Slope} = \dfrac{y_2 - y_1}{x_2 -x_1}\)

AZ:

Finally, to find the y-intercept: The y-intercept is where the line crosses the y-axis. It's also where x is equal to 0. |dw:1613772595960:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!