Mg + H2O --> Mg(OH)2 + H2 If you mix 40 grams of Mg and 60 grams of H2O What is the theoretical yield of H2
First convert from grams to moles like you did in the previous question
The only thing I am confused on is the fact that H2O isn't the limiting reactant and Mg is. I get 1.65 M of Mg and 3.33 M of H2O. the required H2O is 3.29 M but we have more than enough so Mg is the limiting.
Would I flip around the ratio now??? So instead of 2:1 is it 1:2? So I would multiply the 1.65 * 2 because there's 2H2O?
1.65 moles of magnesium and 3.33 moles of water So you are right that Mg will be our limiting reagent
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So we're going to use up all of our magnesium which means all 1.65 moles react. How many moles of water will react with 1.65 moles of Mg?
Would it be the 3.3? because the ratio is 1:2 and 1.65*2 = 3.3? I'm not 100% sure
Yup!
So basically our x is 1.65 and 2x is 3.3 How many moles of the products will we have?
.825 apiece?
Because 1.65/2 = .825 and the products are 1 to 1
nonono Remember it's moles to moles For 1 mole of Mg and 2 moles of H2O, we make 1 mole of Mg(OH)2 and 1 mole of H2 If we're using 1.65 moles of Mg, how many moles of Mg(OH)2 are we forming? Remember it's 1 mole of Mg to 1 mole of Mg(OH)2 And similarly, How many moles of H2 would we make? Remember, it's 1 to 1
So it's 1.65?
Spot on!
Just because we have two products doesn't mean we have to divide by 2 or anything. You just have to keep that moles to mole ratio.
So then the H2 would be 3.33 because we used up all the 1.65 already?
Why would it be 3.33?
How many moles of H2 are there?
1 mole, but didn't we already use up the 1.65 towards the Mg(OH)2?
Sooooo that's not how chemical reactions work haha
There is the law of conservation and all but it doesn't work with the numbers. If you look at the elements then you'll see it's balanced because every atom bonds with another atom and blah blah and so you're not losing anything Just like how we used 40 grams of Mg and 60 grams of water, but the products are not going to add up to 100 grams
It's just moles to mole 1 mole of Mg and 2 moles of water will give us 1 mole of Mg(OH)2 AND the keyword here is AND and 1 mole of of H2
Does that clear it up a little more or are you just as confused?
Ohh so the limiting reagent accounts for both of the products?
yes
OK that clears it up a lot better thanks
Of course!
Now that we have 1.65 H2, all that I have to do is convert that to grams for the theoretical yield
You got it!
And that gets back to 3.33 lol because the molar mass of H2 is 2 and 1.65*2 = 3.33
and that's your theoretical yield :)
I have a question: So I'm not sure if you remember the last problem we did a lil ago, but since the limiting reactant was H2O and it was 2 moles, we had to divide it by 2 to get each of the products, but if it was just 1 mole of H2O, the products would be .277 both?
And thanks for your help again
No problem!
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