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Mathematics 17 Online
FriskIsNice:

Help ;-;

FriskIsNice:

AZ:

Hey there!

Laylalyssa:

I think we have to plug in the value of k into that ..right?

FriskIsNice:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Laylalyssa I think we have to plug in the value of k into that ..right? \(\color{#0cbb34}{\text{End of Quote}}\) Yeah I think so

YECRYHL:

What do u need help with?

Laylalyssa:

\[\frac{3}{2}+\left(-\frac{5}{2}\right)+\left(-2\right)\] this?

AZ:

Plug in k = -5/2 \(\dfrac{3}{2} + \left(-\dfrac{5}{2}\right) + (-2)\) Do you know how to add/subtract fractions? \(\dfrac{3}{2} + \left(-\dfrac{5}{2}\right) = \dfrac{3}{2} - \dfrac{5}{2} = ?\)

Laylalyssa:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @YECRYHL What do u need help with? \(\color{#0cbb34}{\text{End of Quote}}\) theres a question posted a screenshot

FriskIsNice:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Laylalyssa \[\frac{3}{2}+\left(-\frac{5}{2}\right)+\left(-2\right)\] this? \(\color{#0cbb34}{\text{End of Quote}}\) Yeah I believe it should be like that.

AZ:

Oops, I believe you were referring to me and not the OP.

Laylalyssa:

💀no continue💀

AZ:

The question is all yours since you feel this intensely about it :)

Laylalyssa:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ The question is all yours since you feel this intensely about it :) \(\color{#0cbb34}{\text{End of Quote}}\) ok den

FriskIsNice:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ Plug in k = -5/2 \(\dfrac{3}{2} + \left(-\dfrac{5}{2}\right) + (-2)\) Do you know how to add/subtract fractions? \(\dfrac{3}{2} + \left(-\dfrac{5}{2}\right) = \dfrac{3}{2} - \dfrac{5}{2} = ?\) \(\color{#0cbb34}{\text{End of Quote}}\) Yeah I kinda remember how to add/sub fractions, I haven’t done it in a while but I think I know how to

Laylalyssa:

You know how ..so can u give it a try

FriskIsNice:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Laylalyssa You know how ..so can u give it a try \(\color{#0cbb34}{\text{End of Quote}}\) I mean I can try but I think I may get it wrong lol, but I’m gonna try >:)

Laylalyssa:

did u try it or no

AZ:

do you want to show them how to subtract fractions, just to jog their memory :)

Laylalyssa:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ do you want to show them how to subtract fractions, just to jog their memory :) \(\color{#0cbb34}{\text{End of Quote}}\) sure one sec

Laylalyssa:

So for example 6/4 - 10/4 6/4 - 10/4 6/4 + -10/4 6+-10/4 -4/4 = -1 lmk if that made sense 💀

AZ:

basically, when you add or subtract, you have to make sure the denominator is the same. If it is, you can just add or subtract the numerator together \(\dfrac{a}{c} + \dfrac{b}{c} = \dfrac{a+b}{c}\) \(\dfrac{x}{z} - \dfrac{y}{z} = \dfrac{x-y}{z}\)

AZ:

when you're multiplying fractions, the denominator (or the bottom part of the fraction) doesn't matter. You just multiply across. Dividing fractions is a little bit more trickier than that so we'll get to if you have a question that involves that :)

mindfreeze:

take the lcm and solve

jhonyy9:

so i dont wan to interfere nobody's work but first of all i have a question the given equation wan be \[\frac{ 3 }{ 2 }+(-k)+(-2)\] where \[k = - \frac{ 5 }{ 2 }\]

jhonyy9:

yes ?

jhonyy9:

@FriskIsNice

jhonyy9:

i ve wrote it right , correct this equation ?

AZ:

yes, that is what it is

jhonyy9:

ok i m happy that you r here now bc. then you see given this equation with (-k) and the value of k is with minus too so in this way - case what will result ? @AZ please

AZ:

a + (-b) = a - b

jhonyy9:

will result - (-k) what is plus

jhonyy9:

i understand what you say - but i think it in this way @Laylalyssa opinion pls ?

jhonyy9:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 so i dont wan to interfere nobody's work but first of all i have a question the given equation wan be \[\frac{ 3 }{ 2 }+(-k)+(-2)\] where \[k = - \frac{ 5 }{ 2 }\] \(\color{#0cbb34}{\text{End of Quote}}\) in place of k if you substitute the value of k so will result +(-(-5/2)) = +5/2

jhonyy9:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 bc not minus k = -5/2 just k = -5/2 \(\color{#0cbb34}{\text{End of Quote}}\)

AZ:

Good catch! I missed that originally :-)

jhonyy9:

so really i dont wan interfere your calcule - work but - i think this is in this way right

AZ:

You are absolutely correct, we all missed the negative in front of k because we got focused on the fact that k was a negative value

jhonyy9:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ You are absolutely correct, we all missed the negative in front of k because we got focused on the fact that k was a negative value \(\color{#0cbb34}{\text{End of Quote}}\) ty

jhonyy9:

@Laylalyssa pls

jhonyy9:

do you understand it now ?

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