Find the perimeter of the following shape, rounded to the nearest tenth: (pic in replies) 12.5 15.7 16 16.5
Do you know the distance formula?
no...
Have you seen this formula before? \( \text{distance} = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2} \)
nope/
mhmm have you learned about special triangles then perhaps? Such as the 45-45-90 degree triangle Or Pythagoras theorem? a^2 + b^2 = c^2
I know all sides angles equal 180 0-0
thas bout it
To find the perimeter, we have to find the lengths of each side and then add them up
What are the coordinates of point A?
(5,5)
Good! What about point B?
(7,3)?
Perfect! Now to find the length of that side that's between point A and B, we use the distance formula \( d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}\) where you have two points \( (x_1, y_1)\) and \( (x_2, y_2)\)
@AZ
So we have the two points you mentioned (5, 5) and (7, 3) it's in the form of \( (x_1, y_1)\) and \( (x_2, y_2)\) So let's plug in the numbers and simplify, okay?
it would be 2.83?
well if you simplify
\( d = \sqrt{(7- 5)^2 + (3-5)^2} \)
Good! That's one of the sides of our rectangle.
What are the points C and D?
another side would be 5
Yes!!! You can also see that if you drew a triangle with that side as the hypotenuse, that it would form a 3, 4, 5 triangle
so then you add those and multiply by 2 because its a rectangle right?
So now we have |dw:1614032044254:dw|
Yes! Exactly!
15.66??
theres only 15.7 on there. So I think im supposed to round
That's your answer!
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ That's your answer! \(\color{#0cbb34}{\text{End of Quote}}\) thank you!!!
It was my pleasure! :)
Join our real-time social learning platform and learn together with your friends!