**CONJUGATES** Rationalize the denominator and simplify. (SCREENSHOT)
5/4-sqrt3 *4+sqrt3/4+sqrt3 so its 5*(4+sqrt3)/4-(sqrt3)*4+sqrt3). 20+5sqrt3/16-3 = (20+5sqrt3)/13. Hope this helps u
To rationalize the denominator, we have to multiply by the conjugate the conjugate for a+b is a-b the conjugate for a-b is a+b You just switch that sign in the middle
So what is the conjugate of \( 4 - \sqrt{3}\)
uh \[4+\sqrt{3}\] ?
Good! Now we have to multiply both the numerator and denominator by the conjugate. You have to do it to both the numerator and denominator to keep it balanced. It's basically like multiplying by 1 so we're not changing anything but we're able to simplify it. \(\dfrac{5}{4-\sqrt{3}} \times \dfrac{4+\sqrt{3}}{4 + \sqrt{3}} = ?\) remember this formula (a-b)(a+b) = a^2 - b^2
ok
i got
where did that x come from? otherwise, it would be fine
i accidently added x to the question oops
Just remove it and you're good to go! Well done!
thank you !
My pleasure! :)
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