Question

What is the
molarity of a
solution that
contains 85.0
grams sodium
sulfate in 325
mL of solution?

Answer 1

well explain this what exactly are u finding and how

Answer 2

The mass of one mole of Na2SO4 is 142 grams.
0.195 M. 0.599 M. 1.84 M.

Answer 3

so work it out from there if u still need help i can help further

Answer 4

i would help and tell u but thats breaking qcs rules

Answer 5

\(\color{#0cbb34}{\text{Originally Posted by}}\) @KIllerwolf
The mass of one mole of Na2SO4 is 142 grams.
0.195 M. 0.599 M. 1.84 M.
\(\color{#0cbb34}{\text{End of Quote}}\)
noice

Answer 6

Molarity is equal to moles of solute over liters of solution

We have 85.0 grams of sodium sulfate.
We need to first convert that to moles.

Can you find the molar mass of sodium sulfate using the periodic table?

(Alternatively, you can always look it up)
https://www.google.com/search?q=molar+mass+of+sodium+sulfate

The molar mass tells you how many grams of that compound is equal to 1 mole.

So divide 85 by the molar mas to find out how many moles of sodium sulfate you have.

Finally, you have 325 mL of solution. Convert that into Liters. Recall that molarity is moles of solute over LITERS of solution.

1 L = 1000 mL

so to convert 325 mL into L, you need to just divide by 1000.

So to get your final answer of the molarity of the solution,

Molarity = moles / liters

Divide the two values you have gotten so far