8mn5-2m6+5m2n4-m3n3+n6-4m6+9m2n4-mn5-4m3n3 in standard form. I think i have it but want to make sure im teaching my child the right thing
Hello @parikhst ! Welcome to QuestionCove! It would be best for us to write this problem with exponents clearly for it to be easier on the eyes can you confirm that this is the problem we are working with? \(8mn^5-2m^6+5m^2n^4-m^3n^3+n^6-4m^6+9m^2n^4-mn^5-4m^3n^3\)
yes it is. my answer is the standard form which i thought would be n6-6m6+7mn5+14m2n4-5m3n3 sorry bout format
she asked why the n6 comes before the -6m6 because both exponents are 6
hmm I do believe the values with m should come before n because of alphabetical order but let me double check that real quick
thanks
i guess also, is that answer right? lol
now that im reading it may be a different answer where -6m6 is at the end
@AZ I could use some confirmation on this problem as well I think you are making a good point with your latest comment this problem is challenging because all of the values have the same "degree" I believe the correct solution might be: \(-6m^6 -5m^3n^3 +14m^2n^4 + 7mn^5 + n^6\)
so what i was thinkin is to swith the last and first so it would be n6....-6m6
im guessing you do positive numbers first and organize high to low and then go to negatives????
n6+7mn5+14m2n4-5m3n3-6m6
- the variables should be in alphabetical order when alone in each "term" - if the terms have the same degree value, the leading variable should decrease in exponent with each term coming after it (m^6 comes before m^5n, which comes before m^4n^2, which comes before m^3 n^3
I don't think the coefficients play any role in the order of the terms (other than 0 being a bad coefficient to have)
I concur with @Angle 's answer. The the exponents of the first variable decrease as the second variable's exponents increase.
I agree with you @Angle Convention is to have the terms in alphabetical order with the exponents counting down The exponents for the m terms count down (6, 3, 2, 1, 0) I suppose you could have the n exponents count down, but I've seen it mostly with the higher rank letter going for that role. It will depend on what the teacher wants.
so i get that. so is it because m comes before n the -6 is first term is first? if that the case im confused cause there is no option for starting with -6 int the multiple choice answer
ohh if there are multiple choice answers, please share
let me attach a file. she got it wrong and i don't want to give her the wrong answer cause they dont tell u the right one
We can also see that this calculator also simplifies it with -6m^6 at the front https://www.wolframalpha.com/input/?i=8mn%5E5-2m%5E6%2B5m%5E2n%5E4-m%5E3n%5E3%2Bn%5E6-4m%5E6%2B9m%5E2n%5E4-mn%5E5-4m%5E3n%5E3
oh dear ok, in this case we want it where the n^6 exponent is gradually decreasing so n^6 followed by the term with the n^5, then n^4, then n^3
with the term that has no "n" value last
so im confused as to if its the first answer or the last
first answer
the -6m^6 comes last in this case because we apparently want to have the n^6 be the leading variable
so is that standard where n descends first
correct
is there multiple ways of doing these types of problems?
You can think of \(-6m^6\) as \(-6m^6n^0\) because \(n^0 = 1\) assuming n is nonzero.
in this case, yes but as jim mentioned, it seems to be teacher's preference at times like this
would it be ever based the highest exponent and whichever letter correscponds you descend with that first? or am i totally making that up. lets say there was an m8 would u descend w m's first
absolutely correct! It is always first and foremost the highest degree value that comes first in standard form
last question promise! so would this be a correct answer as well -6m6-5m3n3+14m2n4+7mn5+n6
kind of depends on your choices for the question
yes, that would be a correct answer as well
ok awesome thanks soooooo much you guys have been super helpful and i greatly appreciate it!
i would have given her the wrong answer and wrong info otherwise!
absolutely! thanks for coming to questioncove to ask your question :)
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