What happens when H3PO4 gas is passed through a saturated K3PO4 solution? No change is observed. The solubility of K3PO4 in water increases. The solubility of K3PO4 remains the same. K3PO4 will precipitate.
@aZ
Hello! To be able to answer your question, you need to have an understanding of the common-ion effect. "Adding a common ion decreases solubility, as the reaction shifts toward the left to relieve the stress of the excess product. Adding a common ion to a dissociation reaction causes the equilibrium to shift left, toward the reactants, causing precipitation." If you want to review more then click the link: \(\href{https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Supplemental_Modules_(Physical_and_Theoretical_Chemistry)/Equilibria/Solubilty/Common_Ion_Effect#:~:text=decrease%20towards%20K.-,Common%20Ion%20Effect%20on%20Solubility,toward%20the%20reactants%2C%20causing%20precipitation.}{\text{Source: chem.libretexts.org}} \)
or my link
So if \(\text{K}_3\text{PO}_4\) is already saturated, what happens when you add a common ion such as \(\text{PO}_{4}^{3-}\) to the mix?
ehhh, your link is good for understanding the basics of solubility and le Chatelier's principle. However, this question goes beyond that and we're looking at the effects of solubility when you add something else to the equation :)
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ ehhh, your link is good for understanding the basics of solubility and le Chatelier's principle. However, this question goes beyond that and we're looking at the effects of solubility when you add something else to the equation :) \(\color{#0cbb34}{\text{End of Quote}}\) ok thxs
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