A city planner is rerouting traffic in order to work on a stretch of road. The equation of the path of the old route can be described as y = 2/5x − 4. What should the equation of the new route be if it is to be perpendicular to the old route and will go through point (Q, P)? y − Q = -5/2(x − P) y − Q = 2/5(x − P) y − P = -5/2(x − Q) y − P = 2/5(x − Q) ik its not b or d
@dontsaymyname
please help this is time sensitive
@AZ
oop-
i forgot how to do that lol
The slopes of two perpendicular lines multiply to give you -1 So I can see why you would eliminate B and D
The point (Q, P) is in the form of (x, y) so you subtract Q from x and you would subtract P from y
and that's how you would get a line that's perpendicular and goes through the point
so C?
That's correct!
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