Question

The equation of line LM is 5x − y = −4. What is the equation of a line perpendicular to line LM in slope-intercept form that contains point (−3, 2)?

Answer 1

2=-1/5x-3

Answer 2

The answer choices are '
y = 5x + 13
y = negative one fifth x + seven fifths
y = negative one fifth x − seven fifths
y = 5x − 17

Answer 3

The equation of line LM is 5x − y = −4. What is the equation of a line perpendicular to line LM in slope-intercept form that contains point (−3, 2)?

The equation of line LM is 5x − y = −4. What is the equation of a line perpendicular to line LM in slope-intercept form that contains point (−3, 2)?


Since the product of slopes of two perpendicular lines is -1. Hence, the equation of a line perpendicular to line LM in slope-intercept form that contains the point (−3, 2) is . Hence, the correct answer is b) y = negative one fifthx + seven fifths

I hope this help :3

Answer 4

\(\color{#0cbb34}{\text{Originally Posted by}}\) @rocfp
The equation of line LM is 5x − y = −4. What is the equation of a line perpendicular to line LM in slope-intercept form that contains point (−3, 2)?

The equation of line LM is 5x − y = −4. What is the equation of a line perpendicular to line LM in slope-intercept form that contains point (−3, 2)?


Since the product of slopes of two perpendicular lines is -1. Hence, the equation of a line perpendicular to line LM in slope-intercept form that contains the point (−3, 2) is . Hence, the correct answer is b) y = negative one fifthx + seven fifths

I hope this help :3
\(\color{#0cbb34}{\text{End of Quote}}\)
thanks

Answer 5

NP :)