can i get help w/ math please ss below
Geometric sequences are written as \(a_n=a_1r^{n-1}\) \(a_1\) = first term r = rate n = n'th term (Position of the "n" number in the sequence) We need to find the rate first (You can divide the second term over the first. You can recheck whether its true by diving the third term over the second)
\[a _{n} =a _{1}+d(n-1)\] is the formula for arithmetic sequence where \[n\]= nth term \[a _{1}\] = first term \[d\] = common ratio you need to figure the value of the nth term, which is 10
And then after that, the sum of the first nterms of an arithmetic sequence is \[\sum=n((a_{1}+a _{n})/2)\]
\(\color{#0cbb34}{\text{Originally Posted by}}\) @dude Geometric sequences are written as \(a_n=a_1r^{n-1}\) \(a_1\) = first term r = rate n = n'th term (Position of the "n" number in the sequence) We need to find the rate first (You can divide the second term over the first. You can recheck whether its true by diving the third term over the second) \(\color{#0cbb34}{\text{End of Quote}}\) tyy!
oops that was supposed to be the sum, for clarification
np
sum =\[\sum\] So you just have tofind that, first find \[a _{n}\]
ty :)
(:
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