Moments Hw
This is a different problem, but I just want to know if I'm right. Would I add up all the numbers on the left side, and F would be the number that makes the right side added together equal to the left side?
I never exactly passed physics but logic tells me that the position of the weights has an affect on the balance. like the closer it is to the middle affects the tilting less or something
Oh yeah, that is true. I'll look into that thanks Angle
you just have to do 125+375+1000=x+200+100 solve for x
i- ... what did I just say snowflake?
lol, sorry, it's just that your explanation confused me
the distance of the weight away from the center/lever affects the amount of force
and that sounds so complex\(\color{#0cbb34}{\text{Originally Posted by}}\) @Angle the distance of the weight away from the center/lever affects the amount of force \(\color{#0cbb34}{\text{End of Quote}}\) easier to just say the opposite sides of the thing equal each other
lol
nonono you dont understand something like this can be balanced because of the distance away from the middle |dw:1614477575974:dw|
oof, nvmd then lmao
Yeah that's what I initially thought snowflake
\(\color{#0cbb34}{\text{Originally Posted by}}\) @ramen Yeah that's what I initially thought snowflake \(\color{#0cbb34}{\text{End of Quote}}\) oof, we're both dum dum's then lol
Weight x Distance from center = Weight x Distance from center seems to be the formula
i learned something today xD
my logic skills tell me that adding something should be ok so let's do \((125*5)+(375*4)+(1000*1)=(200*1)+(100*3)+(x*5)\) as you can see, I have decided to assign each position a unit
I see what you are trying to do, I can try that first
I got 525 using your formula, which kinda does seem logical but I'm not 100% sure
I got the same
I can't promise you that it's correct (see above: didn't pass physics) but it is definitely going to be more correct than what you or snowflake were trying
Yeah lol, thanks for helping us. Btw it's principles of engineering but it is similar to physics
well good luck with your class... google is your friend
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Angle well good luck with your class... google is your friend \(\color{#0cbb34}{\text{End of Quote}}\) yeppi
Thanks, ohh yeah that's true, I could search this problem up but I'm pretty sure my teacher made this assignment himself so I doubt it would be on google. Or I could just research how to do a similar problem...
yes yes for example, for this problem I searched: "weight distribution on fulcrum formula" which gave the Weight x Distance from center = Weight x Distance from center formula that we used
so I recommend googling the main idea / look for the formula rather than the exact question
Yeah I do see that when I search it up. Thanks for the tips
just to slightly elaborate on what was said before - in terms of physics, you're looking for the torque exerted at each point, which is torque = rFsin(theta) in this case, theta is the angle between the force and the axis, which is 90 degrees, so it basically does reduce down to distance * weight as mentioned before
Join our real-time social learning platform and learn together with your friends!