Question

Triangle ABC has vertices located at A( 0, 2), B (2, 5), and C (−1, 7).

Part A: Find the length of each side of the triangle. Show your work.

Part B: Find the slope of each side of the triangle. Show your work.

Part C: Classify the triangle. Explain your reasoning.

am confused plz help

Answer 1

plz help

Answer 2

@AZ

Answer 3

thats what it looks like when you put it on a graph, the one thats NOT on the graph is not drawn to scale. I just did that one to show what it looks like and to show the angles.

Answer 4

Idk, how to do A and B

But for C, which triangle classification is less than 90*?

Answer 5

to find the length of sides just use the distance formula - hope you know it

@supie

Answer 6

@jhonyy9 to find the slope, would we use rise/run?

Answer 7

The distance formula as in
\(\large{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\)
where d=distance
(x1, x2) the x coordinates
(y2, y1) the y coordinates

@jhonyy9 ?

Answer 8

@Kyky232

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @supie
The distance formula as in
\(\large{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\)
where d=distance
(x1, x2) the x coordinates
(y2, y1) the y coordinates

@jhonyy9 ?
\(\color{#0cbb34}{\text{End of Quote}}\)
yes @supie

Answer 10

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
\(\color{#0cbb34}{\text{Originally Posted by}}\) @supie
The distance formula as in
\(\large{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\)
where d=distance
(x1, x2) the x coordinates
(y2, y1) the y coordinates

@jhonyy9 ?
\(\color{#0cbb34}{\text{End of Quote}}\)
yes @supie
\(\color{#0cbb34}{\text{End of Quote}}\)
good job

Answer 11

Thanks