Question

s (1, 10) a solution to this system of equations?
y= x+5
y= 7x+3

Answer 1

Hey so if it's a solution that means when we plug in x = 1 and y = 10 into BOTH of the equations, it should be true

Answer 2

Hi ~ Karlie !
y = 5x
2x + y = 14
Let's take the second equation and isolate y...
2x + y = 14
Let's subtract 2x from both sides...
-2x+2x+y=-2x+14
SECOND EQUATION...y=-2x+14
FIRST EQUATION.......y=5x
Let's subtract the first equation from the second...
0=-7x+14
Let's add 7x to both sides...
7x+0=7x-7x+14
7x=14
x=2
Let's plug-in x=2 into the first equation..
y=5x
y=(5)(2)
y=10
Let's plug-in x=2 into the second equation to verify y=10...
y=-2x+14
10=[(-2)(2)]+14
10=-4+14
10=10

The two lines meet at (2,10).
Your question asked if these lines meet at (10,2) thus rendering such as a "solution".
The answer is NO.

Answer 3

So for the first equation

y = x + 5

we're plugging in (1, 10)
that means x = 1 and y = 10

put the numbers in
10 = 1 + 5

what is 1 + 5 =?
does it equal to 10?