(05.06)Use a net to find the surface area of the right triangular prism shown below: Three rectangles next to each other with a width of 10 feet. The first and second rectangles' lengths are unknown, and the last is 15 feet long. There are two right triangles above and below the last rectangle. One is labeled with a base of 9 feet and a height of 12 feet. 104 square feet 412 square feet 468 square feet 504 square feet
|dw:1614750711836:dw| There are two right triangles above and below the last rectangle. One is labeled with a base of 9 feet and a height of 12 feet.-- this missed ... do you can post an image about this prism ?
@AZ any idea here pls ? ty.
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 @AZ any idea here pls ? ty. \(\color{#0cbb34}{\text{End of Quote}}\) I don't think the numbers you listed are correct. \( AB \neq BC \neq AC \neq DE \neq DF \neq EF\)
I can't figure out the image but I found a similar question: Three rectangles next to each other with a width of 8 feet. The first and second rectangles length are unknown, and the last is 13 feet long. There are two right triangles above and below the last rectangle. One is labeled with a base of 5 feet and a height of 12 feet. And this is the image:
So for THIS question Three rectangles next to each other with a width of 10 feet. The first and second rectangles' lengths are unknown, and the last is 15 feet long. There are two right triangles above and below the last rectangle. One is labeled with a base of 9 feet and a height of 12 feet. This would be the drawing
|dw:1614784002065:dw|
So to fill in the remaining sides |dw:1614784153126:dw|
To find the surface area @floredan09000 you have to find the area of each rectangle and triangle and add it all together area of rectangle = length * width area of triangle = 1/2 * base * height
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