Question

does anyone know radical 8 time -3 radical 2

Answer 1

\(\sqrt{8} \times -3 \sqrt{2}\)
?

Answer 2

yea that

Answer 3

nvmd, ii wrote it wrong lol

Answer 4

or you could just

\(\sqrt{a} \times \sqrt{b} = \sqrt{a \times b}\)

and in this case, you can easily simplify it

Answer 5

lol, ye that ^

Answer 6

that would be much easier, multiply the insides and the outsides
so it would be -3 times sqrt(8 * 2)

Answer 7

which is -3 sqrt16
do you know how to simply that ^

Answer 8

24 radical 2

Answer 9

so 12

Answer 10

i think

Answer 11

actually... it would be negative
since it would be -3 times 4

Answer 12

you can't multiply a number inside the radical with a number outside

Answer 13

\(\color{#0cbb34}{\text{Originally Posted by}}\) @dariusthegoat95
24 radical 2
\(\color{#0cbb34}{\text{End of Quote}}\)
btw, how'd you get this...

Answer 14

\(\sqrt{8} \times -3 \sqrt{2}\)

\( = -3 \sqrt{8 \times 2}\)

what is 8 * 2 =

Answer 15

He did 3 * 8 @snowflake0531

Answer 16

oh-
lol oop

Answer 17

what is 8 times 2?

Answer 18

i messed somethig up

Answer 19

it will be -12 radical 4

Answer 20

\(\color{#0cbb34}{\text{Originally Posted by}}\) @dariusthegoat95
it will be -12 radical 4
\(\color{#0cbb34}{\text{End of Quote}}\)
ummm not that either
first, what's sqrt 16?

Answer 21

-3 radical 16 is because 16 is a perfect square of 4 so -3 times 4 is -12 with a radical of 4

Answer 22

then there wouldn'tbe a radical anymore

Answer 23

no you were on the right tract

\(\sqrt{16} = 4\)

after that all you have left is -3 * 4

Answer 24

there is no more radical after that

Answer 25

ok thank you

Answer 26

No problem!