Question

help number 9

Answer 1

wrong one

Answer 2

number 10

Answer 3

So i may be wrong, but to solve this you need to take 8000 and add 9%. Correct?

Answer 4

Do you have a calculator to do that?

Answer 5

\(\color{#0cbb34}{\text{Originally Posted by}}\) @sophia333
Do you have a calculator to do that?
\(\color{#0cbb34}{\text{End of Quote}}\)
yes but I think that's wrong but I'm not sure

Answer 6

@az

Answer 7

Wait wait im trying to help you here

Answer 8

So 8000 + 9% is 8720. Now multiply that by 2.

Answer 9

What do ya think the answer is?

Answer 10

16018

Answer 11

No, try again.

Answer 12

17440

Answer 13

@az

Answer 14

Correct

Answer 15

@AZ tell me if im wrong >:C

Answer 16

This is a compound interest question so the formula is

\(\Large A = P(1 + \frac{r}{n})^{nt}\)

we have this new variable called `n` which is how many times the interest is applied in a year

In this question, we say semi-annually so that means n = 2

Answer 17

ok

Answer 18

yea im wrong >:c

Answer 19

so he's borrowing 8,000 this is our P

at 9%- our r
(make sure to change it to a decimal)

and t = 2

Answer 20

.09

Answer 21

@az am i right

Answer 22

So let's plug in all the numbers into the formula, okay?

Answer 23

\(\Large A = P(1 + \frac{r}{n})^{nt}\)

\(\Large A = 8000(1 + \frac{0.09}{2})^{(2~\cdot~2)}\)

So let's take care of the exponent first, what is 2 *2 =

Answer 24

4

Answer 25

Now we have

\(\Large A = 8000(1 + \frac{0.09}{2})^{4}\)

Let's do the fraction

What is 0.09 / 2 =

Answer 26

0.45

Answer 27

check that again, you're missing a 0

Answer 28

.045

Answer 29

now add 1 to it

Answer 30

1.045

Answer 31

now what is (1.045) ^ 4

Answer 32

1.192

Answer 33

So so far, we went from

\(\Large A = 8000(1 + \frac{0.09}{2})^{(2~\cdot~2)}\)

to

\(\Large A = 8000(1.045)^{4}\)

Answer 34

Now just multiply by 8000 and that's your final answer!

Answer 35

9536

Answer 36

And that's your answer!

Answer 37

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
And that's your answer!
\(\color{#0cbb34}{\text{End of Quote}}\)
thxs

Answer 38

You're most welcome!

Answer 39

the second one is the diagram I have to use

Answer 40

Let's ask the new question in another post :)