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Mathematics 9 Online
Someoneee:

So, I need help with this problem: 10x^4y^2z - 20x^3yz^3. I need to factor out the greatest common factor. I have already done so and gotten 10x^3yz for the first part. I need help with the second part. the full answer is either 10x^3yz(xy-2z^2) or 10x^3yz(2xyz-4xyz^2)

snowflake0531:

can you put in a screenshot, that looks so confusing to read like that

AZ:

You're on the right track so far!

AZ:

\( 10x^4y^2z - 20x^3yz^3\) And \(10x^3yz \) is the GCF

Someoneee:

AZ:

The way to simplify it now is Let's look at each individual term \( 10x^4y^2z\) what are you left with when you factor out \(10x^3yz\)

Someoneee:

yep.

AZ:

what do you get

AZ:

\( 10x^4y^2z\) what are you left with when you factor out \(10x^3yz\)

Someoneee:

xyz

AZ:

oops are you sure there's a `z`?

Someoneee:

Whoops my mistake

Someoneee:

x and y

AZ:

Yes! So now we have \( 10x^3yz (xy) \) Now what about the other term \( 20x^3yz^3 \) what do you get when you factor out \( 10x^3 yz\)

Someoneee:

2z^2

Someoneee:

so then it would be 10x^3yz(xy-2z^2)

AZ:

Great!! So now we went from \(10x^4y^2z- 20x^3yz^3 \) to \( 10x^3yz (xy) - 10x^3yz(2z^2) \)

AZ:

That is correct!!!

Someoneee:

Thank you for helping me.

AZ:

And let me show you with some colors so you can remember it forever \( \color{orange}{10x^3yz }(xy) - \color{orange}{10x^3yz}(2z^2) \) if we think of \(10x^3yz\) as `a` we have now \( \color{orange}{a }(xy) - \color{orange}{a}(2z^2) \) and NOW we can factor out `a and we get \( \color{orange}{a }(xy- 2z^2) \) and if we replace `a` back with our \( 10x^3yz\) we'll get \( \color{orange}{10x^3yz}(xy- 2z^2) \)

AZ:

Do you see it now?

Someoneee:

Yes.

AZ:

Great!

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