Question

Simplify.

https://mooreps.owschools.com/media/g_alg01_2016/8/2q10.gif

Answer 1

@AZ

Answer 2

\[\frac{ x }{ y }\sqrt{\frac{ 1 }{ 2y }} = \frac{ x }{ y }\frac{ 1 }{ \sqrt{2y} }= ?\]

any idea now ?

Answer 3

not really no

Answer 4

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
\[\frac{ x }{ y }\sqrt{\frac{ 1 }{ 2y }} = \frac{ x }{ y }×\frac{ 1 }{ \sqrt{2y} }= ?\]

any idea now ?
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 5

multiplie numerator by numerator and denominator by denominator

Answer 6

Simplify \[\sqrt{\frac{ 1 }{ 2y}}\] to \[\frac{ \sqrt{1} }{ \sqrt{2y} }\] and then Simplify \[\sqrt{1}\] to 1 \[\frac{ yx1 }{ x \sqrt{2y} }\] y×1 to y = \[\frac{ y }{ x \sqrt{2y}}\]

Answer 7

oh ok

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @hhanan
Simplify \[\sqrt{\frac{ 1 }{ 2y}}\] to \[\frac{ \sqrt{1} }{ \sqrt{2y} }\] and then Simplify \[\sqrt{1}\] to 1 \[\frac{ yx1 }{ x \sqrt{2y} }\] y×1 to y = \[\frac{ y }{ x \sqrt{2y}}\]
\(\color{#0cbb34}{\text{End of Quote}}\)
how you get this y in numerator ?

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
\[\frac{ y }{ x}\sqrt{\frac{ 1 }{ 2y }} = \frac{ y}{ x }×\frac{ 1 }{ \sqrt{2y} }= ?\]

any idea now ?
\(\color{#0cbb34}{\text{End of Quote}}\)
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 10

because for the rule a/bxc/d=ac/bd and then Simplify yx1 to y

​

Answer 11

yes my bad the first term is y/x not how i ve wrote x/y

Answer 12

but you can simplifie it again

how you eliminate the radical from denominator ?

Answer 13

@hhanan

Answer 14

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
\(\color{#0cbb34}{\text{Originally Posted by}}\) @hhanan
Simplify \[\sqrt{\frac{ 1 }{ 2y}}\] to \[\frac{ \sqrt{1} }{ \sqrt{2y} }\] and then Simplify \[\sqrt{1}\] to 1 \[\frac{ yx1 }{ x \sqrt{2y} }\] y×1 to y = \[\frac{ y }{ x \sqrt{2y}}\]
\(\color{#0cbb34}{\text{End of Quote}}\)
how you get this y in numerator ?
\(\color{#0cbb34}{\text{End of Quote}}\)
multiplie top and bottom by sqrt2y so what will get ?
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 15

\[2x \sqrt{y}\]

Answer 16

\[\frac{ y \sqrt{2y} }{ x \sqrt{2y}*\sqrt{2y} }= ?\]

Answer 17

\[= \frac{ y \sqrt{2y} }{ 2xy } = \frac{ \sqrt{2y} }{ 2x }\]

Answer 18

@Erisgoddes questions ?