Question

physics Question

Answer 1

What's the question?

Answer 2

solve above numerical.@AZ

Answer 3

@AZ

Answer 4

So the y-component stays the same since it's at a fixed height

Do you agree?

Answer 5

Now we're trying to figure out what the x-component is at t = 45 seconds

we know that at t = 30, the x-component is 8.04 * 10^3 m

we need to figure out how fast it is going and then use that to find the distance it would have travelled by 45 seconds

Answer 6

Our first step should be to create a graph to represent our information.



We also have the information that at 0, or the most left side of where the plane is, the plane is 7.60 x 10, and 30 seconds later it's (8.04 x 10) + (7.60 x 10)

Our first step is to find the velocity, wihch is the change in x over the change in time, x/t. Meaning, our first equation is (8.04 x 10^3)/30s. Which gives us 268 m/s.

Since we know that the change in x over the change in time can give us v, we can reverse engineer the equation to gives us the change in x when we use 45 as the change in time. Something like this:

x=V(t)
x=(45)(268)
x=12,060m

Now just square "12,060^2 + 7600^2 which gives us our magnitude of 1.43 x 10m

Answer 7

and to find the orientation/direction

\(\Large \theta = tan^{-1} \left( \dfrac{ P_{45y} } {P_{45x} } \right)\)


remember that \( \vec{P_{45y}}\) remained the same as 7.60 * 10^3

Answer 8

thanks

Answer 9

You're welcome!