Another problem
ok
Do you know how to calculate the slope? @Carson15
I'll throw in colors for you \(\Large\text{Slope} = \dfrac{\color{green}{y_2} - \color{orange}{y_1}}{\color{cyan}{x_2}-\color{red}{x_1}}\) where you have two points \(\Large (\color{red}{x_1}, \color{orange}{y_1})\) and \(\Large (\color{cyan}{x_2}, \color{green}{y_2})\) So you're two points are \((\color{red}{1}, \color{orange}{4})\) and \((\color{cyan}{3}, \color{green}{-2})\)
alright, answer is C. correct?
just worked it out and thats what i got. just running it by u to make sure i didnt mess up
no you've calculated the slope, but remember they're asking for a line that's perpendicular to that and goes through (3, -5)
the slope of the perpendicular line will be the opposite reciprocal
so if the slope is 2 then the OPPOSITE of that is -2 and the RECIPROCAL would make it -1/2
so what is the slope between the two points? and then what would that make the slope of the perpendicular line?
think it would be a since it would be the opposite reciprocal.....if not a
B*
so the equation is y = -1/3 x + b we need to calculate `b` by plugging in (3, -5) so -5 = -1/3 *(3) + b what is b =
-1?
I made a typo, you got the slope of the perpendicular line as 1/3 which is correct so we have -5 = 1/3 *(3) + b what is 1/3 * 3 =
oh lol....1
im assuming the answer is A.
yes, sorry so 1/3 * 3 = 1 so now we have -5 = 1 + b what is b =
its ok lol.....umm, -6 right?
yee
alright, thx
No problem
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