The expression can best be rewritten as ______.
\(\Large\sqrt[c]{a^b} = a^{\frac{b}{c}}\) keep in mind that a normal square root \(\sqrt{a}\) is the same thing as \(\Large\sqrt[2]{a}\)
so is's 3\/9
that's not even an answer choice your question is basically, what is \(\Large \sqrt[2]{9^3}\) use what I just told you above put the numbers in the same order as I put the letters
9 2/3
I have a really dumb question for you but I want to make sure before I put any more effort into this question that it isn't a wasted attempt Are you colorblind?
I will assume the silence means no \( \LARGE\sqrt[\color{red}{c}]{\color{orange}{a}^\color{cyan}{b}} = \color{orange}{a}^{\frac{\color{cyan}{b}}{\color{red}{c}}}\)
so what is \( \LARGE\sqrt[\color{red}{2}]{\color{orange}{9}^\color{cyan}{3}} =\)
27
....
use the colors, mate \(\Large 9^3 \) is not the same thing as 27
ohh you solve it all out but still- that's not what your question is asking you to do
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ I will assume the silence means no \( \LARGE\sqrt[\color{red}{c}]{\color{orange}{a}^\color{cyan}{b}} = \color{orange}{a}^{\frac{\color{cyan}{b}}{\color{red}{c}}}\) \(\color{#0cbb34}{\text{End of Quote}}\) so what is \( \LARGE\sqrt[\color{red}{2}]{\color{orange}{9}^\color{cyan}{3}} =\)
as AZ said, what you have is \( \LARGE\sqrt[\color{red}{2}]{\color{orange}{9}^\color{cyan}{3}}\) and you have to use \( \LARGE\sqrt[\color{red}{c}]{\color{orange}{a}^\color{cyan}{b}} = \color{orange}{a}^{\frac{\color{cyan}{b}}{\color{red}{c}}}\) so basically, from you have to put the numbers from \( \LARGE\sqrt[\color{red}{2}]{\color{orange}{9}^\color{cyan}{3}}\) into \(a^{^{\frac{b}{c}}}\) (a=9, b=3, and c=2) I hope that makes sense ._.
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