Question

PLS HELP FAST. the picture is in the comments

Answer 1

ok

Answer 2

ok

Answer 3

oml im bad at this-

Answer 4

@AZ

Answer 5

@snowflake0531 Anybody gotta do dis i can't wit math i barely have an A

Answer 6

\(\color{#0cbb34}{\text{Originally Posted by}}\) @KazGotFetee
@snowflake0531 Anybody gotta do dis i can't wit math i barely have an A
\(\color{#0cbb34}{\text{End of Quote}}\)
hahahaha

Answer 7

I'm not too good at this, but like-
It's asking what are the values, (there are two, i think), when 87 = 195t -16t^2

Answer 8

how many seconds when the rockets height is 87

Answer 9

smh, you gotta learn it, not just want an answer.
and since I can't be positive I can get this right, wait for @AZ

Answer 10

pog hes here

Answer 11

Yessirski

Answer 12

The equation they give us is \( h= 195 t - 16t^2 \)

`h` is the height at `t` seconds

They want to know at what time the rocket's height is 87

so

\( 87 = 195t - 16t^2\)

Do you know how to solve quadratic equations? @NevaehJade6219

Answer 13

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
The equation they give us is \( h= 195 t - 16t^2 \)

`h` is the height at `t` seconds

They want to know at what time the rocket's height is 87

so

\( 87 = 195t - 16t^2\)

Do you know how to solve quadratic equations? @NevaehJade6219
\(\color{#0cbb34}{\text{End of Quote}}\)
yes

Answer 14

So let's take that 87 to the other side and re-arrange the terms and we'll have

\( -16t^2 + 195t - 87 = 0\)

How do you solve for 't'

Answer 15

OOP! I THINK I GOT THE ANSWER!

Answer 16

You should get two answers for the time

Answer 17

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
So let's take that 87 to the other side and re-arrange the terms and we'll have

\( -16t^2 + 195t - 87 = 0\)

How do you solve for 't'
\(\color{#0cbb34}{\text{End of Quote}}\)
perfect explained help - congrats !

Answer 18

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
You should get two answers for the time
\(\color{#0cbb34}{\text{End of Quote}}\)
then i dont have the answer O_O

Answer 19

How do you want to solve it?

By the quadratic formula?

\(x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}\)

where the equation is \(ax^2 + bx + c\)


or by graphing the function and finding its zeroes or x-intercepts

Answer 20

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
How do you want to solve it?

By the quadratic formula?

\(x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}\)

where the equation is \(ax^2 + bx + c\)


or by graphing the function and finding its zeroes or x-intercepts
\(\color{#0cbb34}{\text{End of Quote}}\)
the formula

Answer 21

\(\color{#0cbb34}{\text{Originally Posted by}}\) @NevaehJade6219
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
How do you want to solve it?

By the quadratic formula?

\(x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}\)

where the equation is \(ax^2 + bx + c\)


or by graphing the function and finding its zeroes or x-intercepts
\(\color{#0cbb34}{\text{End of Quote}}\)
the formula
\(\color{#0cbb34}{\text{End of Quote}}\)
or which ever is easyer

Answer 22

well, do you want to learn or do you want to get the answer fast?

learning means formula
not learning and never knowing means graphing it

Answer 23

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
well, do you want to learn or do you want to get the answer fast?

learning means formula
not learning and never knowing means graphing it
\(\color{#0cbb34}{\text{End of Quote}}\)
getting the answer fast

Answer 24

If you want to graph: https://www.desmos.com/calculator

If you want the formula so we said

\( -16t^2 + 195t - 87 = 0\)

the quadratic formula is

\( x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \)

when the equation is \( ax^2 + bx + c = 0\)

so our
a = -16
b = 195
and c = -87

just plug it into the formula

Answer 25

So you want to graph

https://www.desmos.com/calculator

In the calculator, write

-16x^2 + 195x - 87 = 0

Answer 26

Where does the graph cross the x-axis?

Answer 27

1

Answer 28

. . .

Answer 29

oh wait

Answer 30

If we can't even do things the easy way, how are we ever going to do it the harder way?

Answer 31

.5

Answer 32

...Click on the points

Answer 33

:(

Answer 34

zoom into it, there should be two answers

Answer 35

and give more digits

Answer 36

0.464,0

Answer 37

thats all it says

Answer 38

There we go!! Progress

Answer 39

There's one more, keep moving more to the right

It crosses again one more time

Answer 40

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
There we go!! Progress
\(\color{#0cbb34}{\text{End of Quote}}\)
😥

Answer 41

11.724,0

Answer 42

Good! And do you understand why?

When we throw the ball in the air, it's going to reach 87 feet and then it'll go higher and then it'll come back down to 87 feet. So it's going to be at 87 feet TWICE

that's why we have two answers

Answer 43

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
Good! And do you understand why?

When we throw the ball in the air, it's going to reach 87 feet and then it'll go higher and then it'll come back down to 87 feet. So it's going to be at 87 feet TWICE

that's why we have two answers

Created with RaphaëlReply Using Drawing
\(\color{#0cbb34}{\text{End of Quote}}\)
ok..now what?

Answer 44

those were your two answers

0.464 and 11.724

Answer 45

seconds

Answer 46

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
those were your two answers

0.464 and 11.724
\(\color{#0cbb34}{\text{End of Quote}}\)
oh. that was easier then i thought

Answer 47

but wait...

... there's more

Answer 48

you have to round it to the hundredths

so round it 2 decimal places

and you're all done

Answer 49

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
you have to round it to the hundredths

so round it 2 decimal places

and you're all done
\(\color{#0cbb34}{\text{End of Quote}}\)
i did. and i got the answer right thank you so much

Answer 50

\(\color{#0cbb34}{\text{Originally Posted by}}\) @NevaehJade6219
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
you have to round it to the hundredths

so round it 2 decimal places

and you're all done
\(\color{#0cbb34}{\text{End of Quote}}\)
i did. and i got the answer right thank you so much
\(\color{#0cbb34}{\text{End of Quote}}\)
can you help me with one more thing though...

Answer 51

Graph it.

Answer 52

Firstly, I recommend posting it as a new question.
Secondly, are you familiar with vertex form?

Answer 53

\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531
Firstly, I recommend posting it as a new question.
Secondly, are you familiar with vertex form?
\(\color{#0cbb34}{\text{End of Quote}}\)
um um um umum not really

Answer 54

*Firstly, I recommend posting it as a new question*

Answer 55

\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531
*Firstly, I recommend posting it as a new question*
\(\color{#0cbb34}{\text{End of Quote}}\)
yessir! or maam..

Answer 56

\(\color{#0cbb34}{\text{Originally Posted by}}\) @NevaehJade6219
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
you have to round it to the hundredths

so round it 2 decimal places

and you're all done
\(\color{#0cbb34}{\text{End of Quote}}\)
i did. and i got the answer right thank you so much
\(\color{#0cbb34}{\text{End of Quote}}\)

You are most welcome!