Question

Use the quadratic formula to solve for x.
2x^2+5x=4
Round your answer to the nearest hundredth.
If there is more than one solution, separate them with commas.

Answer 1

@supie any idea ?

Answer 2

i got to\[-5\pm \sqrt{57} \div4\]
WHY DID THAT TAKE ME SO LONG TO WRITE

Answer 3

\(\color{#0cbb34}{\text{Originally Posted by}}\) @artlover03
i got to\[-5\pm \sqrt{57} \div4\]
WHY DID THAT TAKE ME SO LONG TO WRITE
\(\color{#0cbb34}{\text{End of Quote}}\)
but this you dont written it right

for numerator you need using parentheses

Answer 4

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
\(\color{#0cbb34}{\text{Originally Posted by}}\) @artlover03
i got to\[(-5\pm \sqrt{57}) \div4\]
WHY DID THAT TAKE ME SO LONG TO WRITE
\(\color{#0cbb34}{\text{End of Quote}}\)
but this you dont written it right

for numerator you need using parentheses
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 5

wydm? i cant even solve the rest i need help lol

Answer 6

\( x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \)

when the equation is \( ax^2 + bx + c = 0\)

so your equation is
\( 2x^ 2 + 5x - 4 = 0\)

and so yeah, you do get

\( x = \dfrac{ -5 \pm \sqrt{57}}{4} \)

Answer 7

So you're correct so far

Let's separate the answers. Do you have a calculator with you?

Answer 8

\(\pm\) means plus or minus so we have

\( x = \dfrac{ -5 + \sqrt{57}}{4} \)

and

\( x = \dfrac{ -5 - \sqrt{57}}{4} \)

you'll need to use a calculator to find the values of it

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
\( x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \)

when the equation is \( ax^2 + bx + c = 0\)

so your equation is
\( 2x^ 2 + 5x - 4 = 0\)

and so yeah, you do get

\( x_1,2 = \dfrac{ -5 \pm \sqrt{57}}{4} \)
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 10

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
\( x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \)

when the equation is \( ax^2 + bx + c = 0\)

so your equation is
\( 2x^ 2 + 5x - 4 = 0\)

and so yeah, you do get

\( x_1,2 = \dfrac{ -5 \pm \sqrt{57}}{4} \)
\(\color{#0cbb34}{\text{End of Quote}}\)
\(\color{#0cbb34}{\text{End of Quote}}\)
in this way written is right with x_1,2 bc. there are two roots

Answer 11

+= .6374... -= -3.1374...

Answer 12

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
in this way written is right with x_1,2 bc. there are two roots
\(\color{#0cbb34}{\text{End of Quote}}\)

Yes, agreed

Answer 13

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
in this way written is right with x_1,2 bc. there are two roots
\(\color{#0cbb34}{\text{End of Quote}}\)

Yes, agreed
\(\color{#0cbb34}{\text{End of Quote}}\)
explained perfect - good job

Answer 14

\(\color{#0cbb34}{\text{Originally Posted by}}\) @artlover03
+= .6374... -= -3.1374...
\(\color{#0cbb34}{\text{End of Quote}}\)


Good job! So those are your two values for x

Make sure to round to the nearest hundredth

Answer 15

which would be += 0.64 -= -3.14 ?

Answer 16

Correct!

Answer 17

OMG! thank you so much, have a good one!

Answer 18

You too!