Evaluate: C(14, 10)
Here you go
so which answer choice is your answer
can you show me how that works please
Do you see your question It says C(14, 10) the formula is C(n, r) = \(\dfrac{n!}{(n-r)!r!}\) Do you know what `!` means? what factorial means?
no i don't
huh so if you have 4! that means you're multiplying 4*3*2*1 you just keep multiply down until 1 so like 10! = 10*9*8*7*6*5*4*3*2*1
does that make sense?
ok that makes sense
!14= 14 13 12 11 10 9 8 7 6 5 4 3 2 1 like this?
you forgot all the multiplication signs in between
but yeah, you don't really need to multiply it out though look at the formula and look at the answer choices \(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ Do you see your question It says C(14, 10) the formula is C(n, r) = \(\dfrac{n!}{(n-r)!r!}\) \(\color{#0cbb34}{\text{End of Quote}}\)
what number is n and r ?
sometimes I really wish you were joking like idk how to make it any more obvious to you
I'll add colors for you once again It says C(\(\color{red}{14}, \color{orange}{10}\)) the formula is \( \text{C} (\color{red}{n}, \color{orange}{r}) = \dfrac{\color{red}{n}!}{(\color{red}{n}-\color{orange}{r})!\color{orange}{r}!}\) can you at least use the colors to put the numbers where they belong?
ok thanks
so it's the second option?
and then simplify the parenthesis remember if it was 14! - 10! then it can't be simplified without multiplying the two numbers out and doing the subtraction but our equation has (14-10)! so you can do the subtraction inside the parenthesis to get 4!
yeah the second one is correct but that's only because they calculated it and got to the right answer. The third one has it correctly set up but the final answer is incorrect
ok thanks as
no problem Kyle
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