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Mathematics 11 Online
b1az3:

Evaluate: C(14, 10)

b1az3:

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AZ:

Here you go

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AZ:

so which answer choice is your answer

b1az3:

can you show me how that works please

AZ:

Do you see your question It says C(14, 10) the formula is C(n, r) = \(\dfrac{n!}{(n-r)!r!}\) Do you know what `!` means? what factorial means?

b1az3:

no i don't

AZ:

huh so if you have 4! that means you're multiplying 4*3*2*1 you just keep multiply down until 1 so like 10! = 10*9*8*7*6*5*4*3*2*1

AZ:

does that make sense?

b1az3:

ok that makes sense

b1az3:

!14= 14 13 12 11 10 9 8 7 6 5 4 3 2 1 like this?

AZ:

you forgot all the multiplication signs in between

AZ:

but yeah, you don't really need to multiply it out though look at the formula and look at the answer choices \(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ Do you see your question It says C(14, 10) the formula is C(n, r) = \(\dfrac{n!}{(n-r)!r!}\) \(\color{#0cbb34}{\text{End of Quote}}\)

b1az3:

what number is n and r ?

AZ:

sometimes I really wish you were joking like idk how to make it any more obvious to you

AZ:

I'll add colors for you once again It says C(\(\color{red}{14}, \color{orange}{10}\)) the formula is \( \text{C} (\color{red}{n}, \color{orange}{r}) = \dfrac{\color{red}{n}!}{(\color{red}{n}-\color{orange}{r})!\color{orange}{r}!}\) can you at least use the colors to put the numbers where they belong?

b1az3:

ok thanks

b1az3:

so it's the second option?

AZ:

and then simplify the parenthesis remember if it was 14! - 10! then it can't be simplified without multiplying the two numbers out and doing the subtraction but our equation has (14-10)! so you can do the subtraction inside the parenthesis to get 4!

AZ:

yeah the second one is correct but that's only because they calculated it and got to the right answer. The third one has it correctly set up but the final answer is incorrect

b1az3:

ok thanks as

AZ:

no problem Kyle

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