Question

Factor x^2 − 2x + 3.

(x − 3)(x − 1)
(x + 3)(x + 1)
(x − 3)(x + 1)
Prime

Answer 1

what two numbers multiply to give you 3

and add up to -2

Answer 2

since 3 is a positive number and it has to add up to a negative number

that means both the numbers have to be negative

Answer 3

uh, idk

Answer 4

wait.. -3 x -1

Answer 5

x^2 -2x +3 = 0

this quadratic has the discriminant smaller then zero so has non real roots

Answer 6

im confused ._.

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
x^2 -2x +3 = 0

this quadratic has the discriminant smaller then zero so has non real roots
\(\color{#0cbb34}{\text{End of Quote}}\)
so its prime?

Answer 8

what's wrong @snowflake0531 ?

Answer 9

@AZ do you see it now ?

Answer 10

Like, you can't factor it out the regular way

Answer 11

I just saw it too lol.

Answer 12

oh :/

Answer 13

ok, so its prime... thanks for the help :>

Answer 14

ok

Answer 15

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
x^2 -2x +3 = 0

this quadratic has the discriminant smaller then zero so has non real roots
\(\color{#0cbb34}{\text{End of Quote}}\)

ahh, you are correct

Answer 16

so what Jhonyy is saying- you can use the discriminant to tell you about the roots

the discriminant is \( b^2 - 4ac\) when the equation is written as \( ax^2 + bx + c = 0\)

Answer 17

ah, ok I get it now

Answer 18

so

(-2)^2 - 4(1)(3)
= 4 - 12
= -8

since it's negative, we would have imaginary roots

Answer 19

okay I get it

Answer 20

Good :)

Thank you @jhonyy9 for pointing that out, I completely missed it :))

Answer 21

you would have also realized, there are no 2 numbers that can multiply to give you 3 and add up to -2

-3 and -1 would add up to -4 not -2

Answer 22

oh yeah

Answer 23

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ
Good :)

Thank you @jhonyy9 for pointing that out, I completely missed it :))
\(\color{#0cbb34}{\text{End of Quote}}\)
np