Given m \| nm∥n, find the value of x.
(2x+9)=(7x+24)

Question

Hoodmemes · Answer

I'll try and answer this (Warning: I'm not good at math like this is so don't 100% trust my answer, and I'm getting help from a sibling)

I (think) it goes like this :

We can put together the variable terms on one side of the (equation) and then put together constraint terms on another side.

$$(2x-9)+(-7x+9)=(7x-24)+(-7x+9)$$

I'm thinking we can take away the "parentheses"- "()" now

So it would be like this:

$$2x-9+-7x+9=7x-24+-7x+9$$

We now put the expressions in groups of like terms to make em easy

I'll try and answer this (Warning: I'm not good at math like this is so don't 100% trust my answer, and I'm getting help from a sibling)

I (think) it goes like this :

We can put together the variable terms on one side of the (equation) and then put together constant terms on another side.

$$(2x-9)+(-7x+9)=(7x-24)+(-7x+9)$$

I'm thinking we can take away the "parentheses"- "()" now

So it would be like this:

$$2x-9+-7x+9=7x-24+-7x+9$$

We now put the expressions in groups of like terms to make em easy to solve so it would be like :

$$2x-7x-9+9=7x-7x-24+9$$

I'd say solve this side first (2x-7x-9+9)

I think how u do it is that u subtract 2 and 7

$$2x-7x=-5x$$

and now we solve (7x-7x-24+9)

$$7x-7x-24+9\rightarrow-24+9$$

$$-24+9=-15$$

We can divide both (-5x) and (-15) by (5)

So

$$-15\div5=-3$$

take (-3) and make it (3)

and take (-5x) and turn it into (5x)

$$5x \div5= x$$

So I think x=3

(Now this could be wrong so don't fully trust my answer, hope this helps,if it is wrong can somebody explain to me how to do this? )