Question

Can I get some Math help?

Answer 1

I will try, what is the question?

Answer 2

I have two.

Answer 3

Okay. If I can't, then I will tag some people.

Answer 4

Okay. I can't sorry. Umm, ask.

@AZ and @Hoodmemes

Answer 5

@AZ @Hoodmemes

Answer 6

For the first one, you can use

\(\cos (A \pm B) = \cos A \cos B \mp \sin A \sin B\)

we know that sin and cos have periods of 2\(\pi\)

so \( \dfrac{7\pi}{2} + x\) is the same thing as \(\dfrac{\pi}{2} + x\)

Answer 7

Does that help you get the correct answer?

I know usually in calc classes, you aren't even allowed a normal calculator but for homework, you can always graph it out to make sure
I particularly recommend https://www.desmos.com/calculator

Answer 8

I'm still a little confused.

Answer 9

It would be sin x!

Answer 10

careful there

when it's cos(A\(\bf +\)B) then it's going to be cosA cosB \(\bf - \) sin A sin B

Answer 11

so basically 2pi is the period for cos and sin curves

that means we can get rid of 6pi/2 from 7pi/2 because it's basically making the graph the same

that's how we got pi/2

Answer 12

and then cos(pi/2) = 0 so you don't have to worry about that

but you still have the minus

-sinA sin B

and A would be `pi/2` and B is `x`

Answer 13

So would it be -sinx?

Answer 14

there you go!

Answer 15

can you help with the next problem as well?