Question

Lori recently rode her bicycle to visit her friend who lives 4 miles away. On her way there, her average speed was 15 miles per hour faster than on her way home. If Lori spent a total of 1 hour bicycling, find the two rates.

Answer 1

what is the answer

Answer 2

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Answer 3

Ok so its more than one problem you have to solve

Answer 4

Please be mindful that we don't give direct answers here, as the intention of the site is to teach.

That being said: distance = rate*time (abbreviated as d = rt)

we can write one d = rt equation for each trip (once there, and once back)

each trip is 4 miles, so d in both cases is 4

let's also define r = the speed on the way back
t1 = the time it takes to get there
t2 = the time it takes to get back

so for the trip there: "her average speed was 15 miles per hour faster than on her way home" ---> we defined the speed home as r, so the speed there is r + 15

so for the trip there: 4 = (r+15)(t1)

similarly, for the trip back: 4 = (r)(t2)

we also know that the total travel time is 1 hour so t1 + t2 = 1

so now you have enough equations to solve for the unknown r. you can solve t1 + t2 = 1 for t2 by writing t2 = 1 - t1

plug this back into the t2 equation, solve the system for t2, then go back and plug in t2 to solve for r. since wants both rates, also remember to calculate r + 15.

Answer 5

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