What are the values of x and y? A. x equals 9 over 4 and y equals 3 over 4 B. x equals 9 over 4 and y equals 15 over 4 C. x equals 15 over 4 and y equals 5 over 4 D. x equals 3 over 4 and y equals 15 over 4
Here is the ss of the problem
Lemme see
@AZ
question is too hard for my brain to comprehend XD
\(\color{#0cbb34}{\text{Originally Posted by}}\) @ah42632 question is too hard for my brain to comprehend XD \(\color{#0cbb34}{\text{End of Quote}}\) That’s y i called @AZ
So when we have two right triangles like this there's this formula so for the triangle I'm attaching \(\sf \dfrac{BC}{AC} = \dfrac{AC}{DC}\) and \(\sf \dfrac{BC}{AB} = \dfrac{AB}{DB}\) and \(\sf \dfrac{DC}{AD} = \dfrac{AD}{DB}\)
so for your triangle, let's first find 'x' and then we can just use the Pythagorean theorem to find y
so basically if we set it up, we get \(\dfrac{4}{3} = \dfrac{3}{x}\) can you cross multiply and solve for x?
4x and 9?
or 12 and 3x?
you got it \(\dfrac{a}{b} = \dfrac{c}{d}\) would be ad = bc so 4x = 9 what is x = ??
just divide 4 on both sides
2.25
yup!
now the entire length of AC is 4 + 2.25 which equals what?
6.25
and then since it's a big right triangle (AB)^2 + y^2 = AC^2 and AB is 5 and AC is 4 + 2.25 which is 6.25 like you said and so plug it in and solve for y
5^2 + y^2 = 6.25^2 y = ?
those numbers are to the second power right?
yes and I really have to run now so @snowflake0531 will take over :)
ok
Mhm, I'm going to take this a different way lol Proportions \[y/3 = 5/4\] Cross multiply
4y and 15
Yep~ 4y=15 Solve for y y=....
*keep it as a fraction
Divide both sides by 4
3 over 80?
4y=15 Divide each side by 4
3.75 and then as fraction I got 3/80
Division=fraction 15 divided by 4 = 15/4 So, y is 15/4 And we already know that x is 9/4 So, which one is the correct answer
they both are arent they? theyre both for different variables
`So, y is 15/4 And we already know that x is 9/4`
x equals 9 over 4... y equals 15 over 4
ohhhhhhh... I didnt read it correctly. My bad
so you got the answer?
yep
kay
thanks
yw~ altho also thank AZ xd
yessir @AZ thanks
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