can someone help me with this problem? (posted below)
I can try to help you with this, I'm good at math
Did you know, that 9^2 =81?
yes
Oh yeah 9 to power of 2
Okay, So we can change it to 9^2^2x+3 Yes?
i guess so. i've never done that before
So, when we can change the power to 9^2^2x+3 How can we simplify the ^2^2x+3 Do you know how to do that
Therefore when you add those up what do you get?
not really no
\(\color{#0cbb34}{\text{Originally Posted by}}\) @ItzLily Therefore when you add those up what do you get? \(\color{#0cbb34}{\text{End of Quote}}\) no
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Honda not really no \(\color{#0cbb34}{\text{End of Quote}}\) Well, you should learn that, with the base, the otehr exponents, ^2^2x+3, you can multiply them together
So, what is 2(2x+3)?
@snowflake0531 I'm trying to help I know the answer.
I'm helping, can you not see that....
4x+6?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Honda 4x+6? \(\color{#0cbb34}{\text{End of Quote}}\) Yes, and with the same base, we can cancel out the bases So 4x+6 = 3x+1 What is x
@Honda pls check ur dmz
Create equivalent expressions in the equation that all have equal bases, then solve for x .
i'm not sure.
4x+6 = 3x+1 Subtract 3x from each side What do you get
x=5 yes?
No, x= -5
ohh okay. my mistake
So, there's your answer
thats it?
Yep
This is...
thank you!
yw~
Wow..
@snowflake0531 i need help wit data analysis
post it, i'll see if i can help
Mkk
use wolfram alpha
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Positivity use wolfram alpha \(\color{#0cbb34}{\text{End of Quote}}\) what's that?
its a math website for like highschool and higher level math'
oh
does this help?
yeah kinda
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