Question

r^2-9r+20
;-;

Answer 1

Are you trying to factor this

Answer 2

Yes: D

Answer 3

so i get a warning for helping people out now smh ight

Answer 4

\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531
it was since you gave a direct answer i think
\(\color{#0cbb34}{\text{End of Quote}}\)
oh ight so i gotta explain?

Answer 5

yes

Answer 6

;-;

Answer 7

oh ight

Answer 8

;o may i get some help on dis?.

Answer 9

Have you ever done this kind of factoring?
is this new

Answer 10

\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531
Have you ever done this kind of factoring?
is this new
\(\color{#0cbb34}{\text{End of Quote}}\)
yeah ;-;

Answer 11

Okay, so you know that in
x^2 -9x +20
2 integers need to multiply to 20, but add up to -9

Answer 12

Can you think of a factors of 20, that multiply to that and add up to -9?

Answer 13

Factors of 20- 1,2,4.5,10,20?

Answer 14

Yes, they are factors...
But I need `one` pair
For example
1,20
2,10
4,5

By the way, they could all add a negative sign, for example
-1,-20
-2,-10
-4,-5

So, which pair adds up to -9

Answer 15

-4,-5

Answer 16

Yep
that's why we get

(x-4)(x-5)

Answer 17

Ty : D

Answer 18

yw~

Answer 19

If you're interested in how you get to that final answer from finding out that -4 and -5 add to -9 and multiply to 20

\(\large \sf r^2 - 9r + 20\)

Since we know -4 and -5 add to -9 and multiply to 20, we can split the -9r into -4r + (-5r) which is the same thing as -4r - 5r

\(\large \sf r^2 - 4r - 5r + 20\)

Now we factor half of it at a time

\(\large \sf r(r-4) - 5r +20\)

\(\large \sf r(r-4) - 5(r -4)\)

Do you see how we have (r-4) twice? We can factor that out. Since it might look complicated how we're doing it, I'll replace the (r-4) with x instead so you can see it clearly. And then we can switch the x back to (r-4)

\(\large \sf r\color{red}{(r-4)} - 5\color{red}{(r -4)}\)

\(\large \sf r\color{red}{x} - 5\color{red}{x}\)

So now factor out that x from both terms

\(\large \sf \color{red}{x}(r - 5)\)

And remember how we had replaced (r-4) with x. Let's switch it back to what it was originally.

\(\large \sf \color{red}{(r-4)}(r - 5)\)

So now we can say

\(\large \sf r^2 - 9r + 20 = (r-4)(r - 5)\)

Answer 20

I hope that clarifies any doubts/confusion that you may have had :)

Answer 21

o-o Oh tysm : D

Answer 22

No problem (: