Can someone please help me
Acceleration = change in velocity over change in time \(\sf Acceleration = \dfrac{\Delta v}{\Delta t}\)
We know that the acceleration is 0.6 m/s^2 the change in velocity is \( v_f - v_i\) the initial velocity was 0 m/s the final velocity is 12 m/s so what is the change in velocity? and 'x' would be the change in time which we are calculating can you solve for 'x' now?
Yah tnks bro
No problem! Let me know if you want me to check your answer :)
For the second part, remember the formula for acceleration what is the change in velocity in the second stage? that's how you'll know what your acceleration is
Tnks imma do it tomorrow I was just checking if I was going right
sure, sounds good!
So am here
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ For the second part, remember the formula for acceleration what is the change in velocity in the second stage? that's how you'll know what your acceleration is \(\color{#0cbb34}{\text{End of Quote}}\) \(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ For the second part, remember the formula for acceleration what is the change in velocity in the second stage? that's how you'll know what your acceleration is \(\color{#0cbb34}{\text{End of Quote}}\)
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