Question

15x^3 - 12x^2 + 20x - 16

Answer 1

Let's do it by group factoring
15x^3 - 12x^2 + 20x - 16

Let's first factor the first part, 15x^3 -12x^2
What is the GCM?

Answer 2

1?

Answer 3

wait nvm, 3

Answer 4

there's also the x^2

Answer 5

x^2

Answer 6

yes

Answer 7

lol

Answer 8

15x^3 -12x^2
3x^2(5x-4)
yes?

Answer 9

yeah

Answer 10

and then the second half
20x-16
factor that

Answer 11

4

Answer 12

So
4(4x-4)
yea?

Answer 13

yep

Answer 14

\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531
So
4(4x-4)
yea?
\(\color{#0cbb34}{\text{End of Quote}}\)
5x not 4x

Answer 15

ye, 5x, oops

So, we have
3x^2(5x-4) + 4(5x-4)

Do the opposite of how you would usually distribute things
Remember
ab+ac = a(b+C)

Answer 16

Imagine the 5x-4 as just one letter, it'll make it easier to think about

Answer 17

So, then the answer would be (3x^2 - 4)(5x-4)? right?

Answer 18

Huh?
Let's first imagine the 5x-4 as y
So, it would be
3x^2 y + 4y

Do the opposite of distributive property for ^^^ that

Answer 19

Like,
a(b+c)=ab+ac
ab+ac=a(b+c)

Answer 20

The answer would be (3x^2 + 4)(5x - 4). My mistake.

Answer 21

Yepppp