What is the remainder when (2x^4−4x^2−16) is divided by (x+2)
Okay, have you learned either long division for polynomials or synthetic division yet?
prolly but i dont really pay attention
Ok So, which one do you want to use, long division or synthetic division (synthetic division is shorter, easier after youget how to do it
synthetic ig
Okay so we have to set it up For synthetic division, we divide it be (x-_), which means that because int his we are dividing by x+2, we have to use -2
Also, we only write down the coefficients for these
And because we don't have x^3 or x, we fill it in as a 0
ok
|dw:1616170681117:dw| it looks confusing, but each of the numbers are actually just coefficients
ok
And so, we drop down each one, multiply it by -2, but it to above the line, etc., i'll show you|dw:1616170791174:dw|
|dw:1616170804079:dw| multiply 2 and -2
|dw:1616170833673:dw| different than long division, synthetic division does addition
|dw:1616170881777:dw| multiply -2 and -4
|dw:1616170902148:dw| add -4 and 8
|dw:1616170931730:dw| multiply -2 and 4
|dw:1616170954199:dw| add 0 with -8
|dw:1616170978401:dw| mutliply
And so, we are left with 0 at the end if at the end you do not get 0 for once, that means that that is the remainder
So, filling in the gaps again with those x's you get 2x^3 + -4x^2 +4x-8
do i just solve it from there?
._. that's your answer
oh im stupid i swear lol
What we just did was divide you didn't get any of it? oof
the answers im given on the question are -16, -8, 0, and 8
\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531 And so, we are left with 0 at the end if at the end you do not get 0 for once, that means that that is the remainder \(\color{#0cbb34}{\text{End of Quote}}\)
Which means that it is 0
ohh
The division was perfect, there's no remainder
oka i get it
yw~
thanks!
yw~, it was fun
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