Question

Jude says that the volume of a square pyramid with base edges of 9.7 in and a height of 9 in is equal to the volume of a cylinder with a radius of 5.47 in and a height of 3 in. Jude rounded his answers to the nearest whole number. Examine Jude's calculations. Is he correct?


Volume of Square Pyramid Volume of Cylinder
V = one third B(h) V = πr2h
V = one third(94.09)(9) V = π(5.472)(3)
V = one third(846.81) V = π(29.9209)(3)
V = 282 in3 V = π(89.7627)
V ≈ 282 in3
Yes, his calculations are correct and the volumes for figures are equal.
No, he made a mistake in solving for the volume of the cylinder.
Yes, but he made a mistake in solving for the volume of the square pyramid.
No, he made a mistake in solving for the volume of both figures.

Answer 1

No, he made a mistake in solving for the volume of the cylinder.

Answer 2

Mhmm, I don't think so

Where do you think the mistake is?

Answer 3

Volume of Square Pyramid
V = one third B(h)

B = 9.7 * 9.7
h = 9

multiply all the numbers and look at each step, does it look good?

Answer 4

Volume of Cylinder
V = πr^2h

r = 5.47
h = 3

multiply all the numbers and look at each step, does it look good?

Answer 5

If you're too tired

just plug the numbers into
https://www.google.com/search?q=Volume+of+Square+Pyramid

https://www.google.com/search?q=cylinder+volume

Answer 6

282.27?

Answer 7

Oh there equal? thats interesting

Answer 8

yeah, there was no mistakes

Answer 9

Ok great thank you!

Answer 10

No problem!