Blaine steps onto a ski slope with an angle of 25°. There is a coefficient of kinetic friction of 0.15 between him and the ground. He has a mass of 65 kg.
a. Draw the free-body diagram showing the forces acting on Blaine. (1 point)

b. Write the expressions for net force in the x- and y-directions. Be sure to tilt your axis along the incline. (2 points)

c. Calculate the net force and acceleration in the x- and y- directions. (2 points)

Question

Blaine steps onto a ski slope with an angle of 25°. There is a coefficient of kinetic friction of 0.15 between him and the ground. He has a mass of 65 kg.
a. Draw the free-body diagram showing the forces acting on Blaine. (1 point)

b. Write the expressions for net force in the x- and y-directions. Be sure to tilt your axis along the incline. (2 points)

c. Calculate the net force and acceleration in the x- and y- directions. (2 points)

darkknight · Answer

|dw:1616282396657:dw|assuming your situation looks something like this?

darkknight · Answer

in your free body diagram, we will have force of gravity, normal force, and fricti|dw:1616282521111:dw|

darkknight · Answer

in the (y-direction) which would be in the direction of the normal force, here i resolved the force of gravity into its perpendicular and parallel components, so
Fnet(y-direction) = $$F _{perpendicular} +F _{N}$$ and for x direction (down the slope) the parallel component of gravity and friction $$F _{II} +F _{f}$$

darkknight · Answer

you know that the person weighs 65 kg, the angle, and the coefficient of kinetic friction, also $$F _{II}=F _{G}*\sin(25)$$
$$F _{\perp}=F _{G}*\cos(25)$$