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Mathematics 19 Online
snowflake0531:

@AZ

snowflake0531:

3rd

AZ:

okay, so the question is

1 attachment
AZ:

first how can you simplify sec(x) sin(x) remember that sec(x) = 1/cos(x) so what do you get?

AZ:

and then let's work on the denominator and re-write it all in terms of sin and cos what is tan(x) in terms of sin and cos what is cot(x) in terms of sin and cos

AZ:

and then try to simplify the denominator so multiply the fractions so that way you can add them let me know what you get (:

snowflake0531:

I'm stuck I'm at tanx * (sin^2 x + cos^2 x)/cosxsinx)

snowflake0531:

Never minddddddddddd i got it lmao

snowflake0531:

just cross simplify

AZ:

I have no idea how you got that hmm but hopefully you eventually figured it out but yeah \(\dfrac{\tan(x)}{\dfrac{\sin(x)}{\cos(x)} + \dfrac{\cos(x)}{\sin(x)}} = sin^2(x)\)

snowflake0531:

I just changed tan(x) to sinx/cosx and put the division thing to multiplication then i added the denominator thing and so it turned into sinx/cosx * (sin^2 x + cos^2 x)/cosxsinx) then i cross simplified xd

AZ:

if you're cross multiplying, where did you lose the equal sign?

snowflake0531:

? sinx/cosx * (sin^2 x + cos^2 x)/cosxsinx) it turns to 1/cosx * sinx^2 + cosx^2 and then turns into sinx^2

snowflake0531:

i didn't cross multiply i meant like cross simplify when multiplying

AZ:

ohhh I think you mean sinx/cosx * (cosxsinx)/(sin^2 x + cos^2 x)

AZ:

you have the fraction flipped wrong

snowflake0531:

uh, ok oops lol

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