Question

I need help (Stoichiometry)

Answer 1

Which one you think it is

Answer 2

\(\color{#0cbb34}{\text{Originally Posted by}}\) @KynxKatz
Which one you think it is
\(\color{#0cbb34}{\text{End of Quote}}\)
idk that's why I'm asking

Answer 3

Well i cant just give u the answer

Answer 4

okay, so are you going to help me?

Answer 5

Yes

Answer 6

okay

Answer 7

Gimme few minutes

Answer 8

okay

Answer 9

@AZ

Answer 10

The equation is already balanced (always be sure to check)

So looking at the equation, how many moles of K3PO4 and Mg3(PO4)2 are there? Look at the coefficients in front of these compounds

Answer 11

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid
The equation is already balanced (always be sure to check)

So looking at the equation, how many moles of K3PO4 and Mg3(PO4)2 are there? Look at the coefficients in front of these compounds
\(\color{#0cbb34}{\text{End of Quote}}\)
K-3, P-0, O-4 | Mg-3 or 6 idk , P-0 ,O-4 (idk if I'm right)

Answer 12

\(\color{#0cbb34}{\text{Originally Posted by}}\) @TheOfficialDaya
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid
The equation is already balanced (always be sure to check)

So looking at the equation, how many moles of K3PO4 and Mg3(PO4)2 are there? Look at the coefficients in front of these compounds
\(\color{#0cbb34}{\text{End of Quote}}\)
K-3, P-0, O-4 | Mg-3 or 6 idk , P-0 ,O-4 (idk if I'm right)
\(\color{#0cbb34}{\text{End of Quote}}\)
Do you think your right?

Answer 13

Keep in mind we’re talking about compounds, not individual elements

Notice how there’s a 2 at the front of K3PO4 which means 2 moles K3PO4

Can you repeat this logic with Mg3(PO4)2?

Answer 14

\(\color{#0cbb34}{\text{Originally Posted by}}\) @KynxKatz
\(\color{#0cbb34}{\text{Originally Posted by}}\) @TheOfficialDaya
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid
The equation is already balanced (always be sure to check)

So looking at the equation, how many moles of K3PO4 and Mg3(PO4)2 are there? Look at the coefficients in front of these compounds
\(\color{#0cbb34}{\text{End of Quote}}\)
K-3, P-0, O-4 | Mg-3 or 6 idk , P-0 ,O-4 (idk if I'm right)
\(\color{#0cbb34}{\text{End of Quote}}\)
Do you think your right?
\(\color{#0cbb34}{\text{End of Quote}}\)
yea lol

Answer 15

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid
Keep in mind we’re talking about compounds, not individual elements

Notice how there’s a 2 at the front of K3PO4 which means 2 moles K3PO4

Can you repeat this logic with Mg3(PO4)2?
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 16

Remember that no coefficient = implies a 1

Answer 17

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid
Keep in mind we’re talking about compounds, not individual elements

Notice how there’s a 2 at the front of K3PO4 which means 2 moles K3PO4

Can you repeat this logic with Mg3(PO4)2?
\(\color{#0cbb34}{\text{End of Quote}}\)
\(\color{#0cbb34}{\text{End of Quote}}\)
ohh okay, there are 2 moles of K3 or would I not need the 3... there are no moles for P and O unless its 2? i really don't know what to do

Answer 18

ohhh i get it now the answer is D the last bubble

Answer 19

Try to think of Mg3(PO4)2 and K3PO4 as one big chunk of atoms instead of individual K P O atoms

There’s no coefficient (no number in front of) the whole chunk, so there’s only 1 mole. If we had 2(K3PO4) that would be 2 moles, 3(K3PO4) would be 3 moles, etc.

Answer 20

So, we have 2K3PO4 (so 2 moles K3PO4) and 1 mole Mg3(PO4)2 so that’s your mole ratio

Answer 21

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid
Try to think of Mg3(PO4)2 and K3PO4 as one big chunk of atoms instead of individual K P O atoms

There’s no coefficient (no number in front of) the whole chunk, so there’s only 1 mole. If we had 2(K3PO4) that would be 2 moles, 3(K3PO4) would be 3 moles, etc.
\(\color{#0cbb34}{\text{End of Quote}}\)
right okay

Answer 22

So do you still need help with any Subject?

Answer 23

\(\color{#0cbb34}{\text{Originally Posted by}}\) @KynxKatz
So do you still need help with any Subject?
\(\color{#0cbb34}{\text{End of Quote}}\)
no just this one I have another problem

Answer 24

But ill let yk if i get stuck

Answer 25

Mk