Question

Help, ss below.

Answer 1

I have a question, do you know how to do it, and just too lazy to do it xd, or do you have no clue how to do it?

Answer 2

I don't have a clue how to do it.

Answer 3

okie

then wait, let me first do them xd

Answer 4

Okay, so I'll explain what you kinda have to do to do this
1. Imagine the __ as x, each expression multiplied by x, added together, has to equal the other side
2. This is called balancing chemical equations because you have to balance the values, multiplying the expressions by a certain value, kind of like least common multiple ish thing


The first one is pretty easy, you should try it

Answer 5

For example, looking at each side, I can see that the left side as K, but the right side is K (underneath thing) 2

Which means for the first one, I should try to put a 2 in front of it, but then, this means that N is also 2, but the right side has only 1 N, which means I should put a 2 in front of the last expression, to even that out

Answer 6

I think this may be relative but in the assignment, as you said we can use x as the anonymous number.

If I were to take x times 3 would that be the same?

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Astrid1
I think this may be relative but in the assignment, as you said we can use x as the anonymous number.

If I were to take x times 3 would that be the same?
\(\color{#0cbb34}{\text{End of Quote}}\)
wdym

Answer 8

Well when we were using equations the number at teh start of the complete equation is what we would use for the number next to it. Such as,..


\[ _{2}H _{2} +20 \rightarrow 2~H _{2} O \]

We than would take the letters and the numbers.

H= 4 H=2
O=2 O=2

And, yeah.

Answer 9

i'm confused lol
i'll write out the first one for you, give me a minute xd

Answer 10

Okay, I am actually going to get offline, but I should be on later. If not, I will be online at 6 am tomorrow, maybe earlier.

Answer 11

i won't wake up at 6 for you

Answer 12

I know you wont.

Answer 13

hehe, i'll finish those tonight
dm me tomorrow to remind me lol

Answer 14

i finished it xddd
if you come on tonight later, i can help

Answer 15

:)

Answer 16

he did it already for you LOL

Answer 17

and yea, i got the same thing

Answer 18

So, first pulling out the first one

Answer 19

By balancing it, you need the amount of chemicals on each side equal, so, by the end, you should be able to cancel out everything

Answer 20

i mean, the other dude i already did it for you lmaoo

do you want to actual go through on how to do that?

Answer 21

I mean, You he could've just taught me but ig.

I can't read the yellow, are they brackets?

Answer 22

Not necessarily, he just drew them out to show what was being multiplied

Answer 23

Yeh, explain to me that stufff, I don't understand any of it. HELP.

Answer 24

Like,
\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531
For example, looking at each side, I can see that the left side as K, but the right side is K (underneath thing) 2

Which means for the first one, I should try to put a 2 in front of it, but then, this means that N is also 2, but the right side has only 1 N, which means I should put a 2 in front of the last expression, to even that out
\(\color{#0cbb34}{\text{End of Quote}}\)

By putting numbers in front of each part of the each expression, it multiplying each of them by two, the numbers little, on the right down side, will multiply by two.
But each time, because it's multiplying a bunch of ones together, it becomes uneven again
That is why, for the first one, after multiplying the left one by two, you have to relook and see that N will also need to be multiplied by 2

Answer 25

Uh, let me see if the drawing tool will be big enough for me to draw that lol, probably not tho

Answer 26

i have officially realized how difficult it is to draw a 2 and 3-

Answer 27

First off, you can immediately see that the top have has only 1K, while the bottom was has 2
So, we can add a 2 to the beginning of that

Answer 28

And because now that the K has even out, we can see that there are 3 more O's in the top, also 1 more N

This makes us have to multiply the bottom right one by 2 to even that out

(this is the most simplistic kind, usually you'll have to find much more multiples of each expression

Answer 29

then, the easiest way to check work is to write them all out again and see if they cancel one another

Answer 30

Okay.

Answer 31

(those that don't have numbers written in front means that it's 1)
In this case

2K, 2N, 6O, 2H, C, 3O

2K C 3O, 2H, 2N, 6O

Answer 32

And if you match them, they all cancel out at the end-

Answer 33

This balancing is kinda just a guessing game xddddd

Answer 34

Yeah.

Answer 35

Ngl, I am still not getting it.

I know you've been trying, I still barely get it.

Answer 36

sorryyyyyy

Answer 37

It is okay. xD

Answer 38

also btw, you can also look through this ig, it'll help, I think

https://www.webqc.org/balance.php

Answer 39

@Angle Ehh? You capable of helping in this junk?

@Darkknight What about yo darky?

Also, Snowy I've used that link already and I still can't figure out that link.

Answer 40

@AZ - Are you good at this? ._.

Answer 41

Here are some resources:
https://www.wikihow.com/Balance-Chemical-Equations
https://www.instructables.com/How-to-Balance-a-Chemical-Equation-1/#:~:text=In%20order%20to%20balance%20the,until%20both%20sides%20are%20equal.

balancing equations was the only part of chemistry that I could do, but I'm not confident enough to actually explain it well

if you still need help, I can try