Ask your own question, for FREE!
Mathematics 15 Online
Astrid1:

Help. I don't know how to- ;c

Astrid1:

Hewoo:

Which part do you have to simpilfy?

MxxnLight:

@snowflake0531 - @supie - ?

Astrid1:

Well, I am not sure which part I am supposed to simplify.

Astrid1:

You see, I was never taught how to simplify these and I have already contacted my teacher and she says I should know. So I'm left dumbfounded.

QuestionCoveBot:

Simplify all this? Is this one equation, or no?

QuestionCoveBot:

I mean expression, not equation. ._.

Astrid1:

These are multiple expressions. I believe each and everyone is supposed to be simplified.

QuestionCoveBot:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Astrid1 These are multiple expressions. I believe each and everyone is supposed to be simplified. \(\color{#0cbb34}{\text{End of Quote}}\) Ah okay. That makes sense.

snowflake0531:

let supie do it, he knows his stuff xd

Astrid1:

Is 3 x 10^3 times 4 x 10^5 simplified supposed to be.. \[12~ times ~10^8\]

snowflake0531:

Do you want me to walk you through each one?

snowflake0531:

Have you learned the properties of exponents yet?

Astrid1:

I- Idr or idk. I might've. IDKK lc

Tranquility:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Astrid1 Is 3 x 10^3 times 4 x 10^5 simplified supposed to be.. \[12~ times ~10^8\] \(\color{#0cbb34}{\text{End of Quote}}\) You're on the right track

Tranquility:

The exponent rules \( (a^b)^c = a^{bc}\) \( \dfrac{x^y}{x^z} = x^{y-z}\) \( a^b \times a^c = a^{b+c}\)

Astrid1:

Oh yah, I remember those.

Tranquility:

There one or two more exponent properties but these are the only ones you need to solve the remaining questions on your worksheet

QuestionCoveBot:

\[3*10^{3}*4*10^{5}\] \[\frac{ 3^{4} }{ 3}\] \[(4^{2})^{3}\] \[\frac{ 7^{10} }{ 7^{6} }\] \[\frac{ 8*10^{6} }{ 2*10^{3} }\] \[5^{3}*5\] That was a lot to right. ._. So, those are the expressions.

Tranquility:

Let's take a look at your second expression that you have to simplify. \(\dfrac{7^{10}}{7^6} =\) You need to apply this rule: \(\Large \dfrac{a^b}{a^c} = a^{(b-c)}\)

Astrid1:

Do I divide/ or multiply or add both a's together?

Tranquility:

The 'a' just stays the same You only subtract the exponents

Astrid1:

So it's \[7^4\]

Tranquility:

Yes

Tranquility:

For your third expression, keep in mind that \( 3 = 3^1\) How would you simplify \(\dfrac{3^4}{3^1} = ?\)

Astrid1:

3^3?

Tranquility:

Yes. Next one now \( \dfrac{8 \times 10^6}{2 \times 10^3} = ?\)

Astrid1:

I know it would be to the power of 3, but I am stuck because of the 8 and 2.

Tranquility:

Just divide those numbers like normal

Astrid1:

\[4^3?\]

Tranquility:

It won't have an exponent. You can think of it like this \( \dfrac{8 \times 10^6}{2 \times 10^3} = ?\) \( \dfrac{8 \times 10^6}{2 \times 10^3} = \dfrac{8}{2} \times \dfrac{10^6}{10^3} = ?\)

Astrid1:

I- Idk.

Tranquility:

What is \(\dfrac{8}{2} = ?\)

Astrid1:

4.

Tranquility:

We have now: \( \dfrac{8 \times 10^6}{2 \times 10^3} = 4 \times \dfrac{10^6}{10^3}\) What is \( \dfrac{10^6}{10^3} = ?\)

Astrid1:

10^3?

Tranquility:

Yes. Now put it all together. \( \dfrac{8 \times 10^6}{2 \times 10^3} = 4 \times \dfrac{10^6}{10^3} = \boxed{4\times 10^3}\)

Astrid1:

Oh~~~ That makes some sense now.

Tranquility:

Good. Next expression now. \( (4^2)^3\) Use the following property: \(\Large (a^b)^c = a^{bc}\) You just have to multiply the exponents

Astrid1:

So it is \[4^6?\]

Tranquility:

Yes. Now your last expression. \( 5^3 \times 5^5\) Use the following property: \(\Large a^b \times a^c = a^{b+c}\) Just add the exponents

Astrid1:

\[5^8?\]

Tranquility:

That is correct!

Astrid1:

Yay, Thanks so much Tranq.

Tranquility:

You're welcome, Astrid!

Astrid1:

c:

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!