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Astrid1:

Help me. SS below. Or let the math kill me.

Astrid1:

Astrid1:

@QuestionCoveBot Egghead, you said you could help me.

girlygirl:

which one there to many

Astrid1:

Anyways, I need help with all. ;c Someone to check over my work as I go along.

girlygirl:

nvm

Astrid1:

So for number one. \[ 2H _{2} + O _{2} \rightarrow H _{2}O\] H=2 H=2 O=2 O=1 H=4 H=4 O=2 O=2 Right?

Astrid1:

I don't know what I am supposed to put before O on the Reactant side.

QuestionCoveBot:

Are you trying to figure out how much of what makes what? Like how much H2 and O2 makes water?

Astrid1:

No, we have to balance the equations and stuff.

QuestionCoveBot:

Ah okay. Makes more sense. So... I hope you know how much O2 and H2 makes water? I am confused on what you mean by "balance".

Astrid1:

Errrr, It isn't balanced when we get it so then we have to balance the chemical equation. That is why there are blank spots.

QuestionCoveBot:

So your saying... that we have to add the exact amount of H2 and O2 to balance the equation?

Astrid1:

Not nessecarily, Idk how to explain it. ;c

QuestionCoveBot:

Okay, well... you know how much O2 goes with H2 to make H2O?

Astrid1:

Yeah?

Astrid1:

it's \[H _{2}O _{1}\]

QuestionCoveBot:

I'm sorry, I have to get off for a little. I'll be back later. Maybe @carmelle can help.

Astrid1:

Ok ;c

QuestionCoveBot:

All you have to do is add the amount of chemical for all blanks that makes the end result.

Astrid1:

Not entirely, it's much more than that from what I've learned.

QuestionCoveBot:

Hmm okay. What else do you have to do then, other than adding the amount of chemical to the blanks?

Astrid1:

Ahhh, long story ;c

QuestionCoveBot:

Just go ahead and tell it. xD

Astrid1:

If you can understand my notes, I would show you but I can't bc I can't understand it xD

QuestionCoveBot:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Astrid1 If you can understand my notes, I would show you but I can't bc I can't understand it xD \(\color{#0cbb34}{\text{End of Quote}}\) ss the notes.

Astrid1:

OKay.

Astrid1:

Astrid1:

Sorry, The latency sucks on my computer rn.

QuestionCoveBot:

It's okay. I can see it well enough.

Astrid1:

Okay/

hamidiso23:

where the question

QuestionCoveBot:

@snowflake0531

MidNiGhtSkY:

it's making the chemical be more even, like making it into one if that makes any sense.

Astrid1:

I know.

MidNiGhtSkY:

like the number down below, that should be it if im thinking straight :)

Astrid1:

Number down below? o-o

MidNiGhtSkY:

=w= the first one is 2h2+_O2=_h2o

MidNiGhtSkY:

like how manny H2Os can you make if you have 2 H2

MidNiGhtSkY:

technically 4 H's

Astrid1:

Yeah, I wasn't paying attentioj to this, EXT keeps stealing my emojis. But yeah Ik 4.

MidNiGhtSkY:

so if you have 4 h's how many O's do you need to make an even amount of h2os

Astrid1:

2?

MidNiGhtSkY:

o: yes

snowflake0531:

So now that we balanced out 4H + _2O = 4H 2O What times 2O equals 2O

MidNiGhtSkY:

:> you forgot the little- 2 but mk xD means the same thing

snowflake0531:

I'm just putting the small numbers in front of it, so it looks like math

Astrid1:

Yeaaa.

snowflake0531:

So, for the first one, the first blank is 1, the second blank is 2

snowflake0531:

So for the second one, we have _Mg + _2O = __ Mg O

snowflake0531:

You can first automatically see that there are two Os for the first one, so you multiply the right hand side of the equation by 2 _Mg+ _1_ 2O = 2MgO

snowflake0531:

But then, because of this, there are 2 Mgs, which brings you to have to multiply the first one by 2 So the blanks are 2, 1, and 2

MidNiGhtSkY:

:> you let her do the work- please so she can learn how to do it o:

snowflake0531:

Because she doesn't know how to do it, I'm explaining to her, so she can read it through to understand

Astrid1:

mk... Hard to understand but Okay...

AZ:

I got tagged to this post but it seems like that reply was deleted. What part of balancing chemical equations are you still confused about?

AZ:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Astrid1 So for number one. \[ 2H _{2} + O _{2} \rightarrow H _{2}O\] H=2 H=2 O=2 O=1 H=4 H=4 O=2 O=2 Right? \(\color{#0cbb34}{\text{End of Quote}}\) I have no idea what you're counting and why you have re-written the same elements multiple times Let's start all over again This is what we're given \(\sf 2 H_2 + \text{__}O_2 \to \text{__}H_2O\) What do we have on the left hand side of the arrow? We have \(\sf 2 H_2\) and \(\sf O_2\) How many H's are there in \(\sf H_2\) There are 2 H's in \(\sf H_2\) But how many \(\sf H_2\) do we have? We have \(\sf 2 H_2\) so that means we have a total of 4 H's How many O's do we have in \(\sf O_2\) We have 2 O's in \(\sf O_2\)

AZ:

Now let's look at the right hand side after the arrow We have \(\sf H_2O\) How many H's do we have? We have 2 H's How many O's do we have? We have 1 O

AZ:

Now let's compare the left side to the right side |dw:1616715569774:dw| Do you see how we have 4 H's on the left side but only 2 on the right side? We also have 2 O's on the left side but only 1 on the right side So what number do you need to multiply the \(\sf H_2O\) by so that way you can double it so you have the same number of H's and O's on both sides

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