Help me. SS below. Or let the math kill me.
@QuestionCoveBot Egghead, you said you could help me.
which one there to many
Anyways, I need help with all. ;c Someone to check over my work as I go along.
nvm
So for number one. \[ 2H _{2} + O _{2} \rightarrow H _{2}O\] H=2 H=2 O=2 O=1 H=4 H=4 O=2 O=2 Right?
I don't know what I am supposed to put before O on the Reactant side.
Are you trying to figure out how much of what makes what? Like how much H2 and O2 makes water?
No, we have to balance the equations and stuff.
Ah okay. Makes more sense. So... I hope you know how much O2 and H2 makes water? I am confused on what you mean by "balance".
Errrr, It isn't balanced when we get it so then we have to balance the chemical equation. That is why there are blank spots.
So your saying... that we have to add the exact amount of H2 and O2 to balance the equation?
Not nessecarily, Idk how to explain it. ;c
Okay, well... you know how much O2 goes with H2 to make H2O?
Yeah?
it's \[H _{2}O _{1}\]
I'm sorry, I have to get off for a little. I'll be back later. Maybe @carmelle can help.
Ok ;c
All you have to do is add the amount of chemical for all blanks that makes the end result.
Not entirely, it's much more than that from what I've learned.
Hmm okay. What else do you have to do then, other than adding the amount of chemical to the blanks?
Ahhh, long story ;c
Just go ahead and tell it. xD
If you can understand my notes, I would show you but I can't bc I can't understand it xD
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Astrid1 If you can understand my notes, I would show you but I can't bc I can't understand it xD \(\color{#0cbb34}{\text{End of Quote}}\) ss the notes.
OKay.
Sorry, The latency sucks on my computer rn.
It's okay. I can see it well enough.
Okay/
where the question
@snowflake0531
it's making the chemical be more even, like making it into one if that makes any sense.
I know.
like the number down below, that should be it if im thinking straight :)
Number down below? o-o
=w= the first one is 2h2+_O2=_h2o
like how manny H2Os can you make if you have 2 H2
technically 4 H's
Yeah, I wasn't paying attentioj to this, EXT keeps stealing my emojis. But yeah Ik 4.
so if you have 4 h's how many O's do you need to make an even amount of h2os
2?
o: yes
So now that we balanced out 4H + _2O = 4H 2O What times 2O equals 2O
:> you forgot the little- 2 but mk xD means the same thing
I'm just putting the small numbers in front of it, so it looks like math
Yeaaa.
So, for the first one, the first blank is 1, the second blank is 2
So for the second one, we have _Mg + _2O = __ Mg O
You can first automatically see that there are two Os for the first one, so you multiply the right hand side of the equation by 2 _Mg+ _1_ 2O = 2MgO
But then, because of this, there are 2 Mgs, which brings you to have to multiply the first one by 2 So the blanks are 2, 1, and 2
:> you let her do the work- please so she can learn how to do it o:
Because she doesn't know how to do it, I'm explaining to her, so she can read it through to understand
mk... Hard to understand but Okay...
I got tagged to this post but it seems like that reply was deleted. What part of balancing chemical equations are you still confused about?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Astrid1 So for number one. \[ 2H _{2} + O _{2} \rightarrow H _{2}O\] H=2 H=2 O=2 O=1 H=4 H=4 O=2 O=2 Right? \(\color{#0cbb34}{\text{End of Quote}}\) I have no idea what you're counting and why you have re-written the same elements multiple times Let's start all over again This is what we're given \(\sf 2 H_2 + \text{__}O_2 \to \text{__}H_2O\) What do we have on the left hand side of the arrow? We have \(\sf 2 H_2\) and \(\sf O_2\) How many H's are there in \(\sf H_2\) There are 2 H's in \(\sf H_2\) But how many \(\sf H_2\) do we have? We have \(\sf 2 H_2\) so that means we have a total of 4 H's How many O's do we have in \(\sf O_2\) We have 2 O's in \(\sf O_2\)
Now let's look at the right hand side after the arrow We have \(\sf H_2O\) How many H's do we have? We have 2 H's How many O's do we have? We have 1 O
Now let's compare the left side to the right side |dw:1616715569774:dw| Do you see how we have 4 H's on the left side but only 2 on the right side? We also have 2 O's on the left side but only 1 on the right side So what number do you need to multiply the \(\sf H_2O\) by so that way you can double it so you have the same number of H's and O's on both sides
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