Question

math problem

Answer 1

@snowflake0531

Answer 2

@snowflake0531

Answer 3

@dude

Answer 4

kinglegend i screenshotted lol

Answer 5

Honestly, just plot it on Desmos and thencompare that graph with each of the choices

Answer 6

i plotted it on desmos and couldnt find a similar one

Answer 7

snoflake

Answer 8

one sec, let me plot it

Answer 9

Do you know the equation of the graph?

Answer 10

y=f-1(x)

Answer 11

no-
The equation of the line is y=sqrtx+2) +2

Answer 12

yep

Answer 13

now find the inverse of that

Answer 14

f-1(x)=x^2-4x+2

Answer 15

how'd you get that-

Answer 16

im not sure

Answer 17

no, where'd you get that
did you search that up or what

Answer 18

i didnt

Answer 19

mathay

Answer 20

interesting-
you know what, I really don't know-
mathway does say that-, but none of the graphs are quadratic functions

Answer 21

lol

Answer 22

what grade mathare you in lol

Answer 23

my grade is 12th

Answer 24

wat

Answer 25

well, i'll tell you, i'min 8th grade-, i do 11th grade math-, not ur pre-calc lmao

Answer 26

\(\color{#0cbb34}{\text{Originally Posted by}}\) @iuytyuioiuytyuiop

\(\color{#0cbb34}{\text{End of Quote}}\)
just to be clear, this is your f(x)??/

Answer 27

breh it didnt copy

Answer 28

that very first one you sent

Answer 29

it's
sqrt(x+2) +2

Answer 30

yep

Answer 31

\(\color{#0cbb34}{\text{Originally Posted by}}\) snowflake0531
it's
sqrt(x+2) +2
\(\color{#0cbb34}{\text{End of Quote}}\)
the outside plus 2 will shift the graph of a regular sqrt(x) function 2 units up, and the x+2 on the inside of the parenthesis will shift the parent function 2 units to the left, thats what I see in the drawing so this is correct

Answer 32

Now we are going to find the inverse
\[y=\sqrt{x+2}+2\]
Step1: switch the variables x and y
\[x = \sqrt{y+2}+2\]
step 2: SOLVE FOR X
\[x-2=\sqrt{y+2}\]
Square both sides
\[(x-2)^2=y+2\]
I think you can take it away from here

Answer 33

hmmm, looks like since f(x) is a square root function, they only defined it for the top half, so find the graph that has (x-2)^2 -2 = y
You will only find then right side (from the vertex) because the original function was defined for the top (like values higher than the vertex)

Answer 34

yep

Answer 35

\(\color{#0cbb34}{\text{Originally Posted by}}\) darkknight
hmmm, looks like since f(x) is a square root function, they only defined it for the top half, so find the graph that has (x-2)^2 -2 = y
You will only find then right side (from the vertex) because the original function was defined for the top (like values higher than the vertex)
\(\color{#0cbb34}{\text{End of Quote}}\)
if none of that made sense ur good, basically just find which graph matches

Answer 36

@darkknight

Answer 37

gg

Answer 38

i got it correct?

Answer 39

yeah you did